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klasskru [66]
3 years ago
6

Help I need the answer dont send NO FILE only answer if you know it step by step explanation

Mathematics
2 answers:
ra1l [238]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

Start at the given point. Go perpendicular to the line of reflection. It is 1 unit to get there. Now go the same distance, 1 unit, to the other side of the line of reflection. You end up at point (-1, 4). See pic below.

Kazeer [188]3 years ago
3 0

okay, this is pretty simple ! so basically, you are going to reflect the point (p) over the red line that was so nicely placed. since you are are going to imagine the red line is 0,0 (where you would start if you are going to fine the coordinates of a plot point). since the plot point is only one coordinate away from the red line, you would only need to move over one coordinate to the right. If i'm correct, the answer should be -1,4.

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Please someone help me on this daosjdoaisjfseughoe
Roman55 [17]

Answer:7,500

Step-by-step explanation:

no way she gonna make 70 k in a year with that percentage

7 0
3 years ago
What do we call a polynomial with 5 terms
Dafna11 [192]

Answer:

You call an expression with a single term a monimial, an expression with two terms is a binomial and an expression with three terms is a trinomial. An expression with more than three terms is named simply by it's number of terms. For example a polynomial with five terms is called a five-term polynomial.

Step-by-step explanation:

6 0
3 years ago
Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1
Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

x'=\frac{dx}{dt}

a)  x’=t–sin(t),  x(0)=1

dx=(t-sint)dt

Apply integral both sides:

\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k

where k is a constant due to integration. With x(0)=1, substitute:

1=0+cos0+k\\\\1=1+k\\k=0

Finally:

x=\frac{t^2}{2} +cos(t)

b) x’+2x=4; x(0)=5

dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\

Completing the integral:

-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}

Solving the operator:

-\frac{1}{2}ln(4-2x)=t+k

Using algebra, it becomes explicit:

x=2+ke^{-2t}

With x(0)=5, substitute:

5=2+ke^{-2(0)}=2+k(1)\\\\k=3

Finally:

x=2+3e^{-2t}

c) x’’+4x=0; x(0)=0; x’(0)=1

Let x=e^{mt} be the solution for the equation, then:

x'=me^{mt}\\x''=m^{2}e^{mt}

Substituting these equations in <em>c)</em>

m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i

This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>

x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)

Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:

x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}

Finally:

x=\frac{1}{2} sin(2t)

7 0
3 years ago
The radius of a circle can be found by using the formula: r = . If the radius of the circle is 3 cm, find the circumference. Use
Aleonysh [2.5K]
C = 2 * (pi) * r
C = 2 * 3.14 * 3
C = 6 * 3.14
C = 18.84 <===
6 0
4 years ago
Does anyone know where i can get vinnie hackers phone number? thanks!
fomenos

Answer:

search it up

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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