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CaHeK987 [17]
3 years ago
11

If an angle measures more than 90°, then it is an obtuse angle. What is the converse of this statement? Select one: a. If an ang

le is an obtuse angle, then its measure is more than 90°. b. If an angle does not measure more than 90°, then it is not an obtuse angle. c. none of these d. If an angle is not an obtuse angle, then its measure is not more than 90°.
Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0
The answer would be A.) 

because all you are doing is swapping the hypothesis and conclusion.

So, if an angle measures more than 90, then it is an obtuse angle. 

It would be, 

if an angle is obtuse, then the angle measures more than 90. 

Message me on my profile if you need any more help. :) 
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How do you do series with an n
SOVA2 [1]
The problem can be solved step by step, if we know certain basic rules of summation.  Following rules assume summation limits are identical.
\sum{a+b}=\sum{a}+\sum{b}
\sum{kx}=k\sum{x}
\sum_{r=1}^n{1}=n
\sum_{r=1}^n{r}=n(n+1)/2

Armed with the above rules, we can split up the summation into simple terms:
\sum_{r=1}^n{40r-21n+8}=n
=40\sum_{r=1}^n{r}-21n\sum_{r=1}^n{1}+8\sum_{r=1}^n{1}
=40\frac{n(n+1)}{2}-21n^2+8n
=20n(n+1)-21n^2+8n
=28n-n^2

=> (a) f(x)=28n-n^2
=> f'(x)=28-2n 
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0  therefore f(14) is a maximum
(b) f(x) is a maximum when n=14

(c) the maximum value of f(x) is f(14)=196
4 0
3 years ago
What is the range of the function?
AleksAgata [21]
The range of the function on the graph is all real numbers greater than or equal to 2 because the range of a function is what the value of y could be, and y begins at 2 and keeps increasing indefinitely.
Hope this helps!

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
Rasek [7]

Answer:

113-2t√17

Step-by-step explanation:

5 0
3 years ago
When f(x) = x2+9 and g(x) = x-9, find f(x)-g(x).
ohaa [14]

Answer:

\huge{ \boxed{ \sf{ {x}^{2}  - x + 18}}}

Step-by-step explanation:

\underline{ \text{Given}}:

\sf{f(x) =  {x}^{2} +9  \: and \:  g(x) = x-9}

\underline{ \text{To \: find}} :  \sf{ \: f(x) \:  -  \: g(x)}

Put the values:

\mapsto{ \sf{ {x}^{2}  + 9 - ( x  - 9)}}

While subtracting , sign of each term of the second expression changes.

\mapsto{ \sf{ {x}^{2}  + 9 - x + 9}}

Add the numbers : 9 and 9

\mapsto{ \boxed{ \sf{{x}^{2}  - x + 18}}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

5 0
3 years ago
The triangle has side lengths l,m, and n. Find the length of each side and the perimeter of the triangle. (PLEASE SHOW WORK)
erastovalidia [21]

The measure of the sides is 27, 23 and 16 and the perimeter is 56 respectively

<h3>The perimeter of a triangle</h3>

The triangle is a 2 dimensional shape that has 2 sides.

Given the following sides

l = m + n - 12

n = m - 7

m = l - 1/4n

l = m + 1/4n

Substitute

m + 1/4n = m + m - 7 - 12

m + 1/4(m-7) = 2m - 19

m + 1/4m - 7/4 = 2m - 19

-m + 1/4m = -19 + 7/4

-3/4m = -19(4)+7/4

-3/4m = -69/4

-3m = -69

m = 23

Hence the value of m from the given expression is 23

n = 23 - 7

n = 16

l = 23 + 16 -12

l = 39 - 12

l = 27

n = 23 - 7

n = 16

Hence the measure of the sides is 27, 23 and 16 respectively

Perimeter = 27+23+16

Perimeter = 56

Learn more on perimeter of triangle here: brainly.com/question/24382052

#SPJ1

3 0
1 year ago
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