What is this 2x-5+22=?

2 answers:

7 0

<h2><u>Answer:</u></h2><h2><u></u> $\boxed{\boxed{\sf{2x+17}}}$ <u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

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$-5+22=17$

<em> - You could also solve this by flipping the numbers around and subtracting 22 - 5, Which still gives you 17. </em>

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So your answer is $\bold{(2x+17)}$ .

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skelet666 [1.2K]3 years ago

5 0

Answer: 2x+17

Step-by-step explanation: add -5 and 22

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70% of the students applying to a university are accepted. Assume the requirements for a binomial experiment are satisfied for 1

marshall27 [118]

Answer:

a) 0.3826

b) 0.9894

Step-by-step explanation:

We are given the following information:

We treat students accepted at university as a success.

P(students accepted at university) = 70% = 0.70

Then the number of students accepted at university follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

a) P( 8 or more will be accepted)

$P(x \geq 8) = P(x = 8) + P(x = 9) + P(X=10)\\\\= \binom{10}{8}(0.7)^8(1-0.7)^2 + \binom{10}{9}(0.7)^9(1-0.7)^1+ \binom{10}{10}(0.7)^{10}(1-0.7)^0\\\\= 0.2334 + 0.1210 + 0.0282\\= 0.3826$

b) P(4 or more will be accepted)

$P(x \geq 4) =1 - P(x = 0) - P(x = 1) - P(X=2)-P(x=3)\\\\=1 - ( \binom{10}{0}(0.7)^0(1-0.7)^{10} + \binom{10}{1}(0.7)^1(1-0.7)^9+ \binom{10}{2}(0.7)^{2}(1-0.7)^8+ \binom{10}{3}(0.7)^{3}(1-0.7)^7 )\\\\= 1 - 0.0106\\= 0.9894$