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Mathematics

1 answer:

taurus [48]3 years ago

7 0

The answer is 300 min

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Find the solution of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2545%20%5Ctimes%202545%7D%20" id="Te

poizon [28]

Answer:

√{2545×2545}=√2545²=±2545

7 0

2 years ago

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A card is drawn at random from a standard deck of 52 cards. Find the following conditional probabilities. a) The card is a diam

Inga [223]

Answer:

$a.\frac{1}{13}\\b.\frac{1}{2}\\c.\frac{1}{13}\\d.\frac{1}{13}$

Step-by-step explanation:

P(A|B) = P(A and B) / P(B)

Total number of cards = 52

Let A denotes the event that the card is a diamond and B denotes the card is red.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}\\=\frac{\frac{2}{52}}{\frac{26}{52}}\\=\frac{1}{13}$

Let A denotes the event that the card is red and B denotes the card is diamond.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{2}{52}}{\frac{4}{52}}\\=\frac{1}{2}$

Let A denotes the event that the card is nine and B denotes the card is red.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{2}{52}}{\frac{26}{52}}\\=\frac{1}{13}$

Let A denotes the event that the card is a king and B denotes the card is a face card.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{4}{52}}{\frac{12}{52}}\\=\frac{1}{13}$

7 0

2 years ago

How do you factor a polynomial when one root has been given

zloy xaker [14]

So first what you are going to do is divide synthetically your root aka factor into your given equation. Then you are going to kind of guess ands check to find the other factor by synthetically dividing what you have left which should be
x^2 +2x +1 by -5, 5 (to make sure there is no multiplicity), 1, and -1 until you get zero in your remainder spot. The number you used to divide will be your other root.

7 0

3 years ago

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Which expression is equivalent to (9x2y6)−1/2?

galben [10]

Answer:

B. 1/(3xy^3)

Step-by-step explanation:

The minus sign can be dealt with first, then the root taken.

$\left(9x^{2}y^{6}\right)^{-\frac{1}{2}}=\dfrac{1}{\sqrt{9x^{2}y^{6}}}\\\\=\dfrac{1}{\sqrt{9}\sqrt{x^2}\sqrt{y^6}}=\dfrac{1}{3xy^3}$