60 min is 20%of blank min

cehgg A costing system that first assigns costs to activities and then to products is a.job-order costing. b.activity-based cost

Ronch [10]

Answer:b.activity-based costing.

Step-by-step explanation: Activity-based costing is a costing system that first talkies or identifies the activities that are involved in the Manufacturing or in a particular process and them assigns cost to such activities. This type of costing gives high premium or focus on the activities as it assigns cost to products based on the activities that led to the production of the products.

THIS TYPE OF COSTING IS ALSO KNOWN AS ABC APPROACH TO COSTING IT FIRST ASSIGN RESOURCES TO ACTIVITIES AND FROM ACTIVITIES TO PRODUCTS BASED ON THE CONSUMPTION ESTIMATES.

8 0

3 years ago

Find the median and mean of the data set below: 6 , 37 , 2 , 38 , 1 , 3 , 46 6,37,2,38,1,3,46

IgorLugansk [536]

Answer:

Mean: 19

Median: 6

Step-by-step explanation:

8 0

3 years ago

A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,

Andru [333]

Answer:

A. Null and alternative hypothesis:

$H_0: \mu_d=0\\\\H_a:\mu_d\neq 0$

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

$H_0: \mu_d=0\\\\H_a:\mu_d\neq 0$

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848$

The degrees of freedom for this sample size are:

$df=n-1=42-1=41$

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=2\cdot P(t>4.848)=0.00002$

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.02 \cdot 173.283=350$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190$

The 95% confidence interval for the mean difference is (490, 1190).

7 0

3 years ago

What’s is a angle defined

Mashutka [201]

Answer:

the space (usually measured in degrees) between two intersecting lines or surfaces at or close to the point where they meet.

7 0

3 years ago

0.36 as a standard form

NemiM [27]

Answer:

Step-by-step explanation:

4 0

2 years ago