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Readme [11.4K]
3 years ago
5

Can someone please help me with this ​

Mathematics
2 answers:
earnstyle [38]3 years ago
8 0
The answer is C trust me
Elden [556K]3 years ago
3 0

Answer:

d

Step-by-step explanation:

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Please help with 10!
bixtya [17]

Answer:

...

Step-by-step explanation:


4 0
3 years ago
Solve for k, the constant of variation, in an inverse variation problem where y=17 x=6
serious [3.7K]

Answer:

k=102

Step-by-step explanation:

hope this helps with your assignment

6 0
3 years ago
PLEASE HELP
enot [183]

Answer:18.9 miles

1 inch=5.4

3.5 inches =3.5×5.4

=18.9miles

hope this helps

please like and mark as brainliest

7 0
3 years ago
A semicircle is inscribed in an isosceles triangle with base 16 and height 15 so that the
ira [324]

Answer:

  7 1/17

Step-by-step explanation:

A figure can be helpful.

The inscribed semicircle has its center at the midpoint of th base. It is tangent to the side of the isosceles triangle, so a radius makes a 90° angle there.

The long side of the isosceles triangle can be found from the Pythagorean theorem to be ...

  BC² = BD² +CD²

  BC² = 8² +15² = 289

  BC = √289 = 17

The radius mentioned (DE) creates right triangles that are similar to ∆BCD. In particular, we have ...

  (long side)/(hypotenuse) = DE/BD = CD/BC

  DE = BD·CD/BC = 8·15/17

  DE = 7 1/17 ≈ 7.059

8 0
3 years ago
At the age of 22, Vicki opened an IRA. At the beginning of each year, she deposits $1100 into her IRA, which earns 9% annual int
jeyben [28]

Answer:

$51,557.00

Step-by-step explanation:

1100 times 9% = 99 a year

99 times 43 = 4257

1100 times 43 =47,300

then you add 47,300 + 4257 = 51,557

you take your total that she put into the ira and multiply it by 9%

then you multiply that total by the number of years before she retires which is 43

so 99 times 43 = 4257

then you will multiply how much she put in the ira at the beginning of the year which is 1100 by the 43 years before she retires which is 47,300

then you add your totals together

4257 + 47,300 = 51,557

4 0
3 years ago
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