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DIA [1.3K]
3 years ago
7

I need help bad I’m struggling

Mathematics
2 answers:
Likurg_2 [28]3 years ago
4 0

Answer:

30 ft², 40 ft², 70 ft²

jeka57 [31]3 years ago
4 0

Answer:

4th option

Step-by-step explanation:

Applying Pythagoras' identity to the figure

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, then

If the area on the 2sides is 30 ft² and 40 ft² then the hypotenuse is

30 ft² + 40 ft² = 70 ft²

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When 2 pieces of rope are placed end to end they measure 40 meters in length when the 2 pieces are laid side by side one is 10 m
poizon [28]

Answer:

15 meters and 25 meters long

Step-by-step explanation:

<em>There are 2 pieces of rope</em>.

Total length of both---> 40 meters

Length of piece 1 ------> x

Length of piece 2 -----> x + 10

<em>Find the value of x.</em>

<em>Form an equation ----> Length of piece 1 + length of piece 2 = total length</em>

x + (x + 10) = 40

2x + 10 = 40

2x = 30

x = 15

Length of piece 1 --> x ---> 15

Length of piece 2 --> x + 10 ----> 15 + 10 = 25

Therefore, one piece is 15 meters long and the other piece is 25 meters long.

3 0
3 years ago
Please answer<br><br><br>show working out please!!!!!!!!
Nikitich [7]
It's as easy as I solved it

7 0
3 years ago
Read 2 more answers
Suppose that the population​ P(t) of a country satisfies the differential equation dP/dt = kP (600 - P) with k constant. Its pop
jeka94

Answer:

The country's population for the year 2030 is 368.8 million.

Step-by-step explanation:

The differential equation is:

\frac{dP}{dt}=kP(600 - P)\\\frac{dP}{P(600 - P)} =kdt

Integrate the differential equation to determine the equation of P in terms of <em>t</em> as follows:

\int\limits {\frac{1}{P(600-P)} } \, dP =k\int\limits {1} \, dt \\(\frac{1}{600} )[(\int\limits {\frac{1}{P} } \, dP) - (\int\limits {\frac{}{600-P} } \, dP)]=k\int\limits {1} \, dt\\\ln P-\ln (600-P)=600kt+C\\\ln (\frac{P}{600-P} )=600kt+C\\\frac{P}{600-P} = Ce^{600kt}

At <em>t</em> = 0 the value of <em>P</em> is 300 million.

Determine the value of constant C as follows:

\frac{P}{600-P} = Ce^{600kt}\\\frac{300}{600-300}=Ce^{600\times0\times k}\\\frac{1}{300} =C\times1\\C=\frac{1}{300}

It is provided that the population growth rate is 1 million per year.

Then for the year 1961, the population is: P (1) = 301

Then \frac{dP}{dt}=1.

Determine <em>k</em> as follows:

\frac{dP}{dt}=kP(600 - P)\\1=k\times300(600-300)\\k=\frac{1}{90000}

For the year 2030, P (2030) = P (70).

Determine the value of P (70) as follows:

\frac{P(70)}{600-P(70)} = \frac{1}{300} e^{\frac{600\times 70}{90000}}\\\frac{P(70)}{600-P(70)} =1.595\\P(70)=957-1.595P(70)\\2.595P(70)=957\\P(70)=368.786

Thus, the country's population for the year 2030 is 368.8 million.

3 0
3 years ago
100 points
MatroZZZ [7]
The series of transformations that map triangle ABC onto triangle DEF to prove ABC≅DEF is to translation 3 units <span>right then a reflection across x-axis.</span>
5 0
3 years ago
Read 2 more answers
suppose the annual rate of inflation average 3.8% over the next 10 years. the present cost of oil change for tour car is $23.95.
Mariana [72]
If the annual rate in 10 years has the same quadralaterical value the answer would be 47.9 but we can make sure our answer is correct
what we know:

The cost changed in 10 years to 23.95

if the cost changed another 10 years it would be another 23.95, 23.95+23.95=47.9 Which is our answer pls mark brainliest 





4 0
3 years ago
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