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2 years ago

Find the area for 5 and 7

Mathematics

1 answer:

hammer [34]2 years ago

7 0

Answer and Step-by-step explanation:

The area of a circle:

$A = \pi r^{2}$

d = 2r

Plug in the values.

A = $\pi 7^{2}$

A = 49 $\pi$

58 = 2r

r = 29

$A = \pi 29^{2}$

A = $841\pi$

#teamtrees #PAW (Plant And Water)

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3 years ago

Find an equation of the circle that satisfies the given conditions.

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The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \\
x_1=-1 \\ y_1=1 \\ \\ Q(5,9) \\ x_2=5 \\ y_2=9 \\ \\
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The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
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$(-1,1) \\ x_1=-1 \\ y_1=1 \\ \\ (2,5) \\ x_2=2 \\ y_2=5 \\ \\ d=\sqrt{(2-(-1))^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

The radius is 5.

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Billy makes $5 a week in allowance plus $4 for each lawn that he mows.

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Answer:

$15 < $4n + $5

Step-by-step explanation:

We know that Billy needs to make more than $15 between his allowance and the lawns that he mows. This means our inequality should include $15<. Also, since Billy will make $4 per lawn, that means we need to multiply $4 by the number of lawns he needs to mow, n: $4n. So far we have the following: $15<$4n. Next, we know that he makes $5 each week, on top of what he makes mowing each law. This means we need to add the $5 to the $4n. When we put all of these pieces together, we will get the following inequality: $15<$4n+$5

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