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Natasha_Volkova [10]

3 years ago

5

Find the area for 5 and 7

1 answer:

hammer [34]3 years ago

7 0

Answer and Step-by-step explanation:

The area of a circle:

$A = \pi r^{2}$

d = 2r

Plug in the values.

5.

A = $\pi 7^{2}$

A = 49 $\pi$

7.

58 = 2r

r = 29

$A = \pi 29^{2}$

A = $841\pi$

#teamtrees #PAW (Plant And Water)

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If the 9th term of an ap is 1/7 and the 7th term os 1/9 find the 63rd term

Mnenie [13.5K]

Answer:

$a_{63}$ = 1

Step-by-step explanation:

The n th term of an arithmetic progression is

$a_{n}$ = a + (n - 1)d

where a is the first term and d the common difference

use the 9 th term and 7 th term to find a and d

$a_{9}$ = a + 8d = $\frac{1}{7}$ → (1)

$a_{7}$ = a + 6d = $\frac{1}{9}$ → (2)

Subtract (2) from (1) term by term

2d = $\frac{2}{63}$ ⇒ d = $\frac{1}{63}$

Substitute this value into (2) and solve for a

a + $\frac{6}{63}$ = $\frac{1}{9}$

a = $\frac{1}{9}$ - $\frac{6}{63}$ = $\frac{1}{63}$

Hence

$a_{63}$ = $\frac{1}{63}$ + $\frac{62}{63}$ = 1

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