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3 years ago

9

State if the question is BIASED or UNBIASED. Do you pay for your own car insurance?

1 answer:

Sergio [31]3 years ago

6 0

Unbiased because it’s either true or false not an opinion

You might be interested in

Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

8 0

1 year ago

The answer?????????????

Aleksandr-060686 [28]

Hey there!

In a rhombus, opposite angles are congruent. This means that 2y is equal to y+34. Let's set up an equation to solve for y.

2y=y+34

We subtract y from both sides.

y=34

Therefore, y=34°

I hope that this helps! Have a wonderful day!

6 0

2 years ago

5. Heathcliff found a road map showing the driving route to a resort that he knows Gertrude enjoys. The map shows a roadway, sta

tigry1 [53]

$\sqrt{ (8+7)^{2} +(5+3)^{2} } =17$ .
the answer is 17 miles

8 0

2 years ago

Read 2 more answers

One side of a square has endpoints (4.7) and (-3,5). What is the perimeter of the square?

Goryan [66]

Answer:

= 4√53 units

that is option(a)

Step-by-step explanation:

all sides of the square are of the same length

so if we get the length if this side, we can calculate its perimeter

there's this formula,

<u>side length between two points, let's say A(x, y) and B(p, q), is equal to </u>

$\mathsf{ \sqrt{ {(x - p)}^{2} + {(y - q)}^{2} } }$

so here we go,

the same points A and B here are

(4, 7) and (-3, 5)

therefore, side length :-

$= \mathsf{ \sqrt{( {7 - 5})^{2} + {(4 - ( - 3))}^{2} } }$

$= \mathsf{ \sqrt{ {2}^{2} + {7}^{2} } }$

$= \mathsf{ \sqrt{4 + 49} }$

$= \mathsf{\sqrt{53} }$

the side length comes out to be <u>√(</u><u>53</u><u>) </u>

now perimeter of a square is

4 × side length

= 4√53 units

4 0

2 years ago

Will mark brainliest for whoever answers correctly

Maksim231197 [3]

Answer:

1/16

Step-by-step explanation:

2^4=16

7 0

2 years ago