Answer: 4,000
Step-by-step explanation: ok so for this one we are seeing how many times 0.02 goes into 80 0.02*50=1 so then we would 50* 80 and get our answer of 4,000 hope this helped
He now has 3 points I believe
So we know that
Year 1 = $55,000
Year 2 = 55000 + (55,000 x .04) = 55000 + 2200 = $57,200
Year 3 = 57200 + (57200 * .04) = 57200 + 2288 = $59,488
Year 4 = 59488 + (59488 * .04) = 59488 + 2379.52 = $61,867.52
Year 5 = 61867.52 + (61867.52 * .04) = 61867.52 + 2474.70 = $64,342.22
Year 6 = 64342.22 + (64342.22 * .04) = 64342.22 + 2573.69 = $66,915.91
Year 7 = 66915.91 + (66915.91 * .04) = 66915.91 + 2676.63 = $69,592.54
Year 8 = 69592.54 + (69592.54 * .04) = 69592.54 + 2783.70 = $72,376.24
Year 9 = 72376.24 + (72376.24 * .04) = 72376.24 + 2895.05 = $75,271.29
Year 10 = 75271.29 + (75271.29 * .04) = 75271.29 + 3010.85 = $78,282.14
So by the tenth year following graduation, the student would be making $78,282.14 a year. If you add up all of the values (Year 1 thru Year 10) you get a total income over ten years of $660,355.86
Answer: r - 5 = 8
Step-by-step explanation:
From the question, we are informed that Skye ran r laps today at soccer practice while Nadine ran five fewer laps than Skye.
If Nadine ran eight laps at practice, the equation that can be used to find how many laps Skye ran will be:
r - 5 = 8
This means Skye ran 13 laps
Her profit was 126$ because she spent 24$ on her materials and then charged 5$ per 2 so you get 150$ then subtract the 24
(I think)
