Answer:
ΔABC ~ ΔDEC
Step-by-step explanation:
Given : DE║AB
Statements Reasons
1). DE║AB 1). Given
2). ∠CDE ≅ ∠CAB 2). Corresponding angles
[Since DE║AB and AC is the transverse]
3). ∠CED ≅ ∠CBA 3). Corresponding angles
[Since DE║AB and BC is the transverse]
4). ΔABC ~ ΔDEC 4). By AA property of similarity
Hence ΔABC is similar to ΔDEC.
Answer:
10000000000
Step-by-step explanation:
10000000000
:) Hope this helps
Answer:
I think it's prove the midpoints are the same
Step-by-step explanation:
I'm not completely sure but I'm taking it right now and I believe that's the most logical answer because if they meet up at the same midpoint then they could bisect each other.
