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Mandarinka [93]
3 years ago
15

Solve -3(5x-9) please

Mathematics
2 answers:
marissa [1.9K]3 years ago
5 0

Answer:

12

Step-by-step explanation:

Galina-37 [17]3 years ago
3 0

Answer:

−15x + 27

Step-by-step explanation:

You might be interested in
The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.
denis-greek [22]
\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b

which means there is some integer k for which a+b=9k.


Because 9\mid a and 9\mid b, there are integers n_1,n_2 such that a=9n_1 and b=9n_2, and


\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42

We have 42=2\cdot3\cdot7, which means there are four possible choices of n_1,n_2:

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for a,b:

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of a+b is 117.
6 0
3 years ago
HELP PLEASE! and please give out good answers.
hoa [83]
Mean- 2
median- 2
mode- 1&2
range- 3
4 0
2 years ago
Read 2 more answers
Pls help: √5 multiplied by √245
Luden [163]

I believe it is 35!

I hope this helps you, and don't forget to give this answer brainliest if it really helped!

5 0
2 years ago
What is the measure of <rst
Georgia [21]
The measure of RST is:

B: 81

162 is the measure of points RT, so dividing 162 by 2 will give you the angle RST measurements. 
4 0
3 years ago
Read 2 more answers
A rectangular swimming pool has a length twice as long as its width. The pool has a sidewalk around it that is 2 feet wide. Writ
xxMikexx [17]

Answer:

A_p=2w^2

A_s=12w+16

Step-by-step explanation:

Functions and Geometry

Sometimes we need to express areas, volumes, and distances in terms of unknown quantities (or variables). When we can find such expressions, they can be referred to as functions. Let's recall the area of a rectangle is A=wl, being w its wide and l its length

Please refer to the image below. The length of the swimming pool is l and its width is w. Its area is

A_p=lw

We know the length is twice as long as its width, l=2w, so

A_p=(2w)w=2w^2

A_p=2w^2

The sidewalk is 2 feet wide. The length of the pool and its sidewalk is

l'=l+4

Similarly, the width of the pool+sidewalk is

w'=w+4

The area of the pool+sidewalk is

A'=l'w'=(l+4)(w+4)=lw+4l+4w+16

We know that l=2w, so

A'=(2w)w+4(2w)+4w+16

A'=2w^2+12w+16

The area of the sidewalk alone is the subtraction of both areas

A_s=A'-A_p=2w^2+12w+16-2w^2

Simplifying

A_s=12w+16

7 0
3 years ago
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