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Ira Lisetskai [31]
3 years ago
8

The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0
\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b

which means there is some integer k for which a+b=9k.


Because 9\mid a and 9\mid b, there are integers n_1,n_2 such that a=9n_1 and b=9n_2, and


\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42

We have 42=2\cdot3\cdot7, which means there are four possible choices of n_1,n_2:

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for a,b:

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of a+b is 117.
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Answer:

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Step-by-step explanation:

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Now, the vertex is given as (0,3) which is at x = 0, y = 3.

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Answer:

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Step-by-step explanation:

7x(x+4)\\\\Multiplication\ is\ distributive\ on\ addition\\\\\Rightarrow 7x(x+4)=7(x\times x+x\times 4)\\\\7x(x+4)=7(x^2+4x)\\\\Multiplication\ is\ distributive\ on\ addition\\\\\Rightarrow 7x(x+4)==7\times x^2+7\times 4x\\\\7x(x+4)=7x^2+28x

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25 points
lbvjy [14]

Answer:

unit_4_study_guide_solutions.pdf

Step-by-step explanation:

This link is a study guide, and on the LAST PAGE it has the answer to your question!

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