Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So



has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.
The answer is 20!
you need to change the subtraction sign to an addition sign and change -4 to a 4. then, solve!
hope this helps!!
Answer:
C will be the rightful answer
Answer:
not idea sorry but 4 no is idea it can be solve the 10 std
Answer:
2
Step-by-step explanation:
2 + 6 - 6
8 - 6
2
2 would be the answer