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Iteru [2.4K]
2 years ago
7

(PLEASE HELP) Which value of x makes this equation true -90=-100+x

Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
8 0

Answer:

-0.9

Step-by-step explanation:

-0.9 × 100 = -90

Mariulka [41]2 years ago
4 0

answer : -90 = -100+x → x = 10

explanation : to solve for x, you are simplifying both sides of the equation, then isolating the variable.

step 1 : move the variable to the left-hand side and change its sign.

ex : -90-x = -100

step 2 : move the constant to the right-hand side and change its sign.

ex : -x = -100+90

step 3 : calculate the sum

ex : -x = -10

step 4 : change the signs on both sides of the equation

ex : x = 10

solution : x=10

hope this helps !

- audrey ♡

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An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
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Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

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