How to do the problem:
Assuming that you mean you want 12% of the number 80 and showing work, here is the answer:
To get X percent of any number, write the percent as a decimal and then multiply that decimal by the whole.
What I mean:
You want 12% of 80
so first change 12% into a decimal
12% is equal to .12 as a decimal
Then multiply that decimal by the whole
Since you want 12% of 80, 80 is the whole
that means you do .12 * 80
which is equal to 9.6
<u>Thus(answer)</u>
12% of 80 = 9.6
1/3= 5/15
2/5= 6/15
5/15 + 6/15 = 11/15
15/15 - 11/15 = 4/15
Part C= 4/15
× equals negative 4 i think and y equals -3
4/7 is the simplest form
You can divide 20 by 5 and get 4 and divide 35 by 5 and get 7
Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
; 
