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3 years ago

There are 56 workers during each shift. The workers are split into teams of 14 each. How many work during a shift?

Mathematics

1 answer:

Over [174]3 years ago

5 0

Answer:

4 teams

Step-by-step explanation:

To evenly distribute 14 into 56, you divide. 56/14 is 4.

Therefore the correct answer is 4 teams.

Hope I helped!!!

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How do I Express the inequality x < 7 using interval notation.

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Answer: $(-\infty, 7)$

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====================================================

Explanation:

Think of x < 7 as writing $-\infty < x < 7$

So x is between negative infinity and 7, excluding both endpoints.

To write $-\infty < x < 7$ in interval notation, we write $(-\infty, 7)$

The curved parenthesis tell us to exclude the endpoint.

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3 years ago

What is the mode of this problem

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Answer:

Miss, I would like to have a refund for both of my mcchickens that cost 9 dollars each. I would also like to have a refund for both of my drinks that cost 3 dollars each. They are both large. You messed up my whole meal!

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3 years ago

4 1/5 ÷ 2/3 as a mixed number in simplest form

Lady_Fox [76]

Answer:

Step-by-step explanation:

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2 years ago

Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for</u> $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

3 years ago

There are 56 workers during each shift. The workers are split into teams of 14 each. How many work during a shift?​

There are 56 workers during each shift. The workers are split into teams of 14 each. How many work during a shift?