Answer:
The answer to your question is V2 = 23.52 l
Explanation:
Data
Volume 1 = V1 = 22.5 l
Pressure 1 = P1 = 734 mmHg
Volume 2 = V2 = ?
Pressure 2 = 702 mmHg
Process
To solve this problem use Boyle's law.
P1V1 = P2V2
-Solve for V2
V2 = P1V1 / P2
-Substitution
V2 = (734 x 22.5) / 702
-Simplification
V2 = 16515 / 702
-Result
V2 = 23.52 l
-Conclusion
If we diminish the pressure, the volume will be higher.
There is no way to know which reaction requires which catalyst. However, if you apply copper to a reaction where it does act as a catalyst, the rate of reaction will be much faster as it lowers the activation energy for successful collisions.
The answer is B, the number of protons
It's is the unique thing about every element!
Answer:
ΔH = -55.73 kJ/mol
Explanation:
Since the density of water is 1 g/ml and the problem wants us to use this value to find the mass of NaOH and HNO3 we arrange the original equation of
Since no heat was lost or gained
qrxn+qsoln=0. ----> qrxn=-qsoln.
qsol = mc*()
The mass of the solution is the mass of NaOh and HNO3. 100+100= 200.
You plug in the remaining numbers using 4.18 as the heat capacity and 2 as the change in temperature:
qsol=200*(4.18)*(2)= 1672 J
qrxn= -1672 J
Now ΔH = qrxn over the amount in moles or grams. This problem asks for NaOH in moles. To calculate this we use the concentration formula
M= . -----> n=V*M.
Note that you must convert 100 ml to L to use this equation. So we have
n=0.1*0.300 where n=0.03
ΔH =
ΔH = -55733.3 J/mol
ΔH = -55.73 kJ/mol
The flame that comes out of the Bunsen burner. it's blue/pale violet.