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Answer:
16.499 × 10∧ 21 atoms
Explanation:
Given data:
mass of P2O5= 0.560 g
number of atoms= ?
first of all we will calculate the molar mass of P2O5:
P = 2×31 g/mol = 62 g/mol
O = 5× 16 = 80 g/mol
molar mass of P2O5 = 142 g/mol
Noe we will find the moles of 0.560 g P2O5:
moles = mass / molar mass
moles = 0.560 g/ 142 g/mol
moles = 0.0039 mol
now we will find the atoms present in 0.0039 moles:
0.0039 × 6.02 × 10∧ 23 molecules
2.357 × 10∧ 21 molecules
P2O5 consist of 7 atoms:
2.357 × 10∧ 21 × 7 = 16.499 × 10∧ 21 atoms
Answer:
2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction
Explanation:
2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction
Rb is a +1 cation, NO3 is a -1 anion, Be is a +2 cation and F is a -1 anion.
In writing an ionic compound the charge of the cation becomes the subscript of the anion and the charge of the anion becomes the subscript of the cation.
So the ionic compound formed between Be2+ and F- is BeF2. The ionic compound formed between Be2+ and NO3- is Be(NO₃)₂.
As there are two NO₃ on the product side it is balanced by writing a 2 coefficient before RbNO₃ on the reactant side.
And as there are two F on the reactant side it is balanced by writing a 2 coefficient before RbF on the product side.
Answer:
(S)−1−iodo−2−methylbutane
Explanation:
This reaction involves the substitution of iodine for bromine in (S)−1−bromo−2−methylbutane. The reaction proceeds with retention of configuration because the product is (S)−1−iodo−2−methylbutane. There is no change in the configuration of the product compound when the reaction is carried out in acetone which is a polar aprotic solvent. The reaction is shown in the image attached.
