First problem.
Call a and b the sides. Since the sides are doubled they are 2*a and 2*b
You know the area is given by a*b.
2a*2b = 12
4ab = 12
So divide both terms for 4 :)
ab = 3 ft^2
Second problem.
Find the volume of the two solids.
The first contenitor is a parallelepiped.
V = abh
a = 10
b = 5
h = 6
V = 10*5*6 = 300 in^3
The second solid is a cilinder.
V = pi*r^2*h = 3^2*10*pi = 9*10*pi = 90pi in^3 = 90*3,14 = 282,6 in^3
The first contenitor hold more ice cream
Answer:
-9
14≅ -0.6428571
Step-by-step explanation:
Answer:
Given
if p:q=2/3:3 and p:r=3/4:1/2, calculate the ratio p:q:r giving your answer in its simplest form
We need to find the ratio p:q:r
Given p:q = 2/3 : 3 = 2/3 / 3 = 2/9
and p : r = 3/4 : 1/2 = 3/4 / 1/2 = 3/2
Now p/q = 2/9 and p/r = 3/2
We need to make p equal numerators so we get
p/q = 2/9 x 3/3 = 6/27 and
p/r = 2/3 x 3/2 = 6/4
Therefore p : q : r = 6 : 27 : 4
#9- -1.42
#10- .04
#11- .232
#12- 6.6
#13- 4 505/1000
#14- -11/100
#15- 62/100
#16- -1 74/100
