Ask question

Ask question

All categories

3 years ago

14

Determine the equivalent system for the given system of equations:

1 answer:

NeTakaya3 years ago

4 0

Answer:

$\large\boxed{B.\ \left\{\begin{array}{ccc}2x+3y=7\\6x+y=11\end{array}\right}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+3y=7&(1)\\4x-2y=4&(2)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}2x+3y=7\\4x-2y=4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad6x+y=11\qquad(3)\\\\\text{Make the system of equation with (1) and (3):}\\\\\left\{\begin{array}{ccc}2x+3y=7\\6x+y=11\end{array}\right$

You might be interested in

The admission fee to an amusement park is $28. It costs an additional p dollars to rent a locker to hold your belongings. The to

Nezavi [6.7K]

it costs 8 dollars to rent a locker because

28x5=140

180-140=40

40/5= 8

6 0

3 years ago

Please help! - Kim needs to place 32 mystery books and 56 biography books on library shelves. She is to place the maximum number

Oksi-84 [34.3K]

A. 8 books on each shelf
B. 4 shelves for mystery, 7 shelves for biography

3 0

3 years ago

Read 2 more answers

HELP HELP HELP<br> HELP HELP <br> HELP <br> (STEP BY STEP)

Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

$2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1$

Then factorizing the difference of squares, $x^2-1=(x-1)(x+1)$ , we end up with

$\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}$

3 0

2 years ago

PLEASE SOLVE AND CHECK. SHOW COMPLETE SOLUTION

Alex17521 [72]

<u>Solution</u><u>:</u>

$\sqrt{4x + 13} = x + 2$

First square both sides.

$= > ( \sqrt{4x + 13} ) ^{2} = (x + 2) ^{2}$

Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

$= > 4x + 13 = {(x)}^{2} + 2 \times x \times 2 + (2) ^{2} \\ = > 4x + 13 = {x}^{2} + 4x + 4$

Now, transpose 4x and 4 to LHS.

$= > 4x - 4x + 13 - 4 = {x}^{2} \\$

Now, do the addition and subtraction.

$= > {x}^{2} = 9 \\ = > x = \sqrt{9} \\ = > x = ±3$

<u>Answer</u><u>:</u>

<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>

Hope you could understand.

If you have any query, feel free to ask.

3 0

2 years ago

Ines has saved $5. She doubles the amount she saves each week. Does the function have a constant difference or a constant ratio?

salantis [7]

Answer:

The function have a constant ratio

No, it does not represent an exponential function.

Step-by-step explanation:

As given,

Ines has saved $5. She doubles the amount she saves each week.

⇒ In first week she saved = $5

In second week she saved = 2×$5 = $10

In third week she saved = 2×$10 = 20

In fourth week she saved = 2×$20 = 40

and so on..

∴ we get the series

5, 10, 20, 40 ,.......

If the series is given as a, b, c, d, ..... , then

The common difference is defined as d = b-a = c-b

The common ration is defined as r = $\frac{b}{a} = \frac{c}{b}$

Here, in the given question

The series is - 5, 10, 20, 40

This has no common difference , d = 10 - 5 (= 5 )≠ 20 - 10 (= 10)

As 5 ≠ 10

So the function does not define common difference .

Now,

This has common ratio , r = $\frac{10}{5} (=2) = \frac{20}{10}(=2)$

As 2 = 2

So, the function represent common ratio

Now,

The function does not represent an exponential function because it is increased by common ratio.

7 0

3 years ago