We have that
y=-3x²<span>+5x+11
we know that
the equation of the parabola in standard form can be expressed in one of the following two ways
y=ax</span>²+bx+c
<span>the parabola opens up if a is positive and opens down if a is negative
and
x=ay</span>²+by+c
the parabola opens right if a is positive and opens left if a is negative
<span>
in this problem
the equation is of the form
</span>y=ax²+bx+c<span>
a=-3
so
the parabola opens down
using a graph tool
see the attached figure
the vertex of a parabola is a maximum
the answer is</span>
the parabola opens down
Answer:
C
Step-by-step explanation:
multiply through by 10
10{4.8(x-4)} = 10(-0.2x) + 10(15.8)
48(x-4) = -2x + 158
48x - 192 = -2x +158
48x + 2x = 158 + 192
50x = 350
divide through by 50
x=350/50
x=7
therefore, answer = C
Answer:
the first one
Step-by-step explanation:
the 4x's cancel out and 8 does not equal -14 so...
11x12-(-8)x(-1)
132+8x(-1)
132-8
124
Answer:
a) If c=3662 then q=228 and r=14.
b) If c=-3662, then q=-229 and r=2
Step-by-step explanation:
a) Observe that 229*16=3664, since r must be in the interval [0,16), then 229 doesn't work, but 228*16=3648 and 3662-3648=14.
Then 3662=228*16+14.
b) Observe that -228*16=-3648 and -3648-14=-3662, but r= must be positive. Then -228 doesn't work.
But observe that -229*16=-3664 and -3664+2=-3662. So -3662=-229*16+2