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3 years ago

Pls I NED HELP ASAP I ONLY HAVE 10 MINUTES

Mathematics

2 answers:

vampirchik [111]3 years ago

8 0

Answer:

Step-by-step explanation:

x= 20

3x+5 replace x with 5 than do 3x5=15+5=20

Fed [463]3 years ago

4 0

Answer:

Step-by-step explanation:

when a letter and a number are next to each other u have to multiply, so x is 5 so 3 x 5 is 15. 15 plus 5 is 20 so 20 is ur answwer

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What is the solution to the system of equations below? Y=-4/5x-6 & y=-30

Ainat [17]

So when you are trying to find the solution to the system of equations make sure that you have it where y= -4/5x-6 and y= -30 are written like this:

-30=-4/5x-6

And then solve for x:

Add 6 on both sides.

-24=-4/5x

Then multiply by the reciprocal of -4/5.

-5/4*-24=-5/4*-4/5x

x=30

But then you are gonna want to plug 30 in for x in y=-4/5x-6 to make sure that it is the same as y=-30.

5 0

3 years ago

Read 2 more answers

Having trouble on these type of questions. an explaination would be greatly appreciated

Kazeer [188]

Answer: easy peasy so your answer would be 4=(6x7)x12 so what you would do is take the first two and dived them your answer you want to dived it with your other numbers

Step-by-step explanation:

8 0

3 years ago

Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye

Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let $\rho(x,y)$ be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

$m=\int\limits \int\limits_D \rho(x,y) \, dA$ .

From the question, the given density function is $\rho (x,y)=xye^{x+y}$ .

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

$I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx$ .

Since D is a rectangular region, we can apply Fubini's Theorem to get:

$I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx$ .

Let the inner integral be: $I_0=\int\limits^1_0xye^{x+y}dy$ , then

$I=\int\limits^1_0(I_0)dx$ .

The inner integral is evaluated using integration by parts.

Let $u=xy$ , the partial derivative of u wrt y is

$\implies du=xdy$

and

$dv=\int\limits e^{x+y} dy$ , integrating wrt y, we obtain

$v=\int\limits e^{x+y}$

Recall the integration by parts formula: $\int\limits udv=uv- \int\limits vdu$

This implies that:

$\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy$

$\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}$

$I_0=\int\limits^1_0 xye^{x+y}dy$

We substitute the limits of integration and evaluate to get:

$I_0=xe^x$

This implies that:

$I=\int\limits^1_0(xe^x)dx$ .

$I=\int\limits^1_0xe^xdx$ .

We again apply integration by parts formula to get:

$\int\limits xe^xdx=e^x(x-1)$ .

$I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(-1)=1$ .

No unit is given, therefore the mass of the lamina is 1.

3 0

3 years ago

Problem 10-01 NPV A project has an initial cost of $66,950, expected net cash inflows of $14,000 per year for 9 years, and a cos

svlad2 [7]

Answer:

NPV = $13,676.33

Step-by-step explanation:

First, find the present value of the cash inflows. You can solve this question using a Financial calculator;

14,000 per year is a recurring cashflow hence the PMT

PMT = 14,000

I/Y = 10%

N= 9

FV =0

then CPT PV = 80,626.33

NPV = -Initial investment + PV of future cash inflows

NPV = -66,950 + 80,626.33

NPV = $13,676.33

"NPV" button, then , then "CPT".

The answer to the NPV = $13,676.33

5 0

2 years ago

(x^3)^9 = <br> A: x^12 <br> B: x^27 <br> C: x^3 <br> D: x^6

Grace [21]

$(x^3)^9=x^{27}$

3 0

3 years ago