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3 years ago

Help!!!! How to round this ASAP pls!!!!!

Mathematics

2 answers:

34kurt3 years ago

8 0

It would be 2 bc u couldn’t round 0 because it’s less then 5

Mekhanik [1.2K]3 years ago

3 0

$\text{Hello there!}\\\\\text{The thousandths place is the 3rd place after the decimal}\\\\\text{This means that 2 would be your thousandths place, since it's the third }\\\text{digit after the decimal}\\\\\text{We would see that the number next to it is 8, since 8 is a big number,}\\\text{we would round two up by 1}\\\\\text{This would make: 2.023}\\\\$

$\text{Tip: If the number to the right of the number you're rounding is between}\\\text{1-4, keep the number the same. If it's 5-9, round up by 1}\\\\\boxed{\text{Answer: 2.023}}$

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Please answer correctly !!!!!!!!! Will mark brianliest !!!!!!!!!!!!

makkiz [27]

Answer:

g(x) has a greater y intercept than f(x)

Step-by-step explanation:

f(x) = 6x^2 + 18x +3

f(0) = 0+0+3

The y intercept is 3

g(x) crosses the y axis at 6

The y intercept is 6

g(x) has a greater y intercept than f(x)

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3 years ago

A particle is moving with the given acceleration function and initial conditions. Find the velocity function and the position fu

Lerok [7]

Answer:

The velocity function is the particle is $v(t)=-2\cos (t)-4\sin (t)-1$ .

Step-by-step explanation:

The acceleration function of a moving particle is

$a(t)=2\sin (t)-4\cos (t)$

The initial conditions are v(0) = −3, s(0) = 5.

Integrate the acceleration function with respect to time to find the velocity function.

$\int a(t)=\int (2\sin (t)-4\cos (t))dt$

$v(t)=-2\cos (t)-4\sin (t)+C_1$

Use the initial condition v(0) = −3 to find the value of C₁.

$-3=-2\cos (0)-4\sin (0)+C_1$

$-3=-2(1)-4(0)+C_1$

$-3=-2+C_1$

$-3+2=C_1$

$-1=C_1$

So the velocity function is the particle is

$v(t)=-2\cos (t)-4\sin (t)-1$

Integrate the acceleration function with respect to time to find the position function.

$\int v(t)=\int (-2\cos (t)-4\sin (t)-1)dt$

$s(t)=-2\sin (t)+4\cos (t)-t+C_2$

Use the initial condition s(0) = 5 to find the value of C₂.

$5=-2\sin (0)+4\cos (0)-(0)+C_2$

$5=-2(0)+4(1)+C_2$

$5=4+C_2$

$1=C_2$

So, the position function is the particle is $s(t)=-2\sin (t)+4\cos (t)-t+1$ .

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3 years ago

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PolarNik [594]

No.

Inside a circle, where the lines are drawn inside a 300 degrees angle will correspond with a 60 degrees angle, but the shaded parts are different. However, there is technically no such thing as a negative angle, so your answer is No.

hope this helps

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3 years ago

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motikmotik

Answer:

E': (-3, 3)

F': (-1, 2)

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Step-by-step explanation:

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klemol [59]

A is correct. Hope my answer helped u :)

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