Answer:
<h3>y + 2 = 3/7(x-7)</h3>
Step-by-step explanation:
The point-slope form of the equation will be expressed as;
y - y0 = m(x-x0) where;
m is the slope
(x0, y0) is the point on the line
Given
Slope m = 3/7
Point (x0, y0) = (7, -2)
Substitute into the equation;
y - y0 = m(x-x0)
y - (-2) = 3/7 (x - 7)
<em>y + 2 = 3/7(x-7)</em>
<em>Hence the equation in point-slope form is y + 2 = 3/7(x-7)</em>
All you have to do is combine like terms. 2c and (-c) are like terms (-5b) and (-b) are like terms and a is a term. So, 2c combined with (-c) is C. (-5b) and (-b) combined is (-6b). Since a doesnt need to be combined with anything, you leave it as it is so your answer will then be c - 6b + a (this is the answer assuming that there is a + in front of the a. If there is a - sign, then just change your +a to -a at the end
Step-by-step explanation:
Lines that are tangent to a circle are perpendicular to the radius of the circle.
Lines that are tangent to a circle are congruent
I believe the answer should be 77
Slope =(9+3)/(-2-4) = 12/-6 = -2
Y+3 = -2 (×-4) => y=-2×+5
D is the line asked
Slope: -1/3
D: y-6 = -1/3 (×-3) or y= -1/3× + 7
