All categories

3 years ago

Please help with the 2 questions ive attached, i dont understand it at all

Mathematics

1 answer:

vesna_86 [32]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

(a)

Consider the denominator

To obtain 5xy from x , multiply by 5y

Thus numerator is multiplied by 5y, that is

$\frac{1}{x}$ = $\frac{5y}{5xy}$

(b)

Consider the numerator

To obtain 5ab² from ab, multiply by 5b

Thus denominator is multiplied by 5b, that is

$\frac{ab}{2c}$ = $\frac{5ab^2}{10bc}$

You might be interested in

What is the volume of the rectangular prism?

11Alexandr11 [23.1K]

The volume is 288

because V = w h l = 6•4•12 = 288

8 0

3 years ago

What is the factored form of 3x+24y? 3(x+8y) 3xy(x+8y) 3(3x+24y) 3xy(3x+24y)

Artyom0805 [142]

Answer:

Option A. 3(x+8y)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Im cond=fused on it and really need help to continue<br> to pass my classes

maxonik [38]

Answer:

http://www.calcul.com/show/calculator/recurring-decimal-to-fraction?i=0.02...

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Someone help me solve this expression please

Alex

Step-by-step explanation:

To solve, we have to remember PEMDAS (Parenthesis, Exponent, Multiply / Divide, Add or Subtract).

Here, the curly brackets act as parenthesis, so we solve that first.

• 3 + 7 = 10

Then, we multiply by 4.

• 10 • 4 = 40

Finally, we add 6 to 40.

• 40 + 6 = 46.

Our final answer: 46

6 0

3 years ago

Read 2 more answers

Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B

Galina-37 [17]

Answer:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

8 0

3 years ago