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spin [16.1K]
4 years ago
12

Why is 0.77 greater than 0.077

Mathematics
1 answer:
nekit [7.7K]4 years ago
5 0

Answer: because the 7 in 0.77 is in the tens place, while 0.077 has a 0 in the tens place, and 7 is greater than 0.

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Need help plz plz you will get rewarded need this answer by 3:37 only 5 mins plz plz pL is this correct
Hunter-Best [27]

Answer:

Your answers are correct!!! I just cant see the top as i told u in the details place....

Please brainlest...

Step-by-step explanation:

5 0
3 years ago
Find the surface area of the cone that has a lateral height of 4.2 and a diameter of 2.8. Use 3.14 for π.
Anvisha [2.4K]

Answer:

here look for it there is a sol

Step-by-step explanation:

https://www.careerlauncher.com/cbse-ncert/class-9/Math/CBSE-SurfaceAreasandVolumes-NCERTSolutions.html

5 0
3 years ago
ASAP<br> Can someone please help me with this
mote1985 [20]

Answer:

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4 0
3 years ago
Oliver read for 450450450 minutes this month. His goal is to read for 10\, percent more minutes next month. If Oliver meets his
dybincka [34]

Step-by-step explanation:

450450450=100%

? =110%

110×450450450/100

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7 0
3 years ago
Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800. A researcher from the a
Doss [256]

Using the z-distribution, it is found that she should take a sample of 46 students.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800, hence, by the Empirical Rule the standard deviation is found as follows:

6\sigma = 800 - 200

6\sigma = 600

\sigma = 100

The sample size is n when M = 29, hence:

M = z\frac{\sigma}{\sqrt{n}}

29 = 1.96\frac{100}{\sqrt{n}}

29\sqrt{n} = 196

\sqrt{n} = \frac{196}{29}

(\sqrt{n})^2 = \left(\frac{196}{29}\right)^2

n = 45.67.

Rounding up, a sample of 46 students should be taken.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
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