Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
No because solids can't transmit heat by convection, and convection only works because of hotter and quicker moving molecules have a lower density so they rise to the surface. But in a solid, the molecules can't move relative to each other. They only vibrate :)
Answer:
x = -1, -5
Step-by-step explanation:

Hope it helps.
Don't forget to click the "Brainliest" button if you like my answer.
Answer: D
The reason I say d is because the positive 3 is where the 9 is at on the y-axis
Hey any chance you remember the work answer for the problem? I have the same question also!