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ladessa [460]
3 years ago
15

A marching band was in a parade. the band members marched in 8 rows. there were 6 band members in each row. explain how the fact

that 5 x 6=30 can help you find 8 x 6.
Mathematics
1 answer:
natta225 [31]3 years ago
6 0
If 5 x 6 = 30 you can figure out 8 x 6 by adding 6 three times to 30!

30 + 6 = 36

36 + 6 = 42

42 + 6 = 48 <-- the answer is 48!
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Answer:

57.420

Step-by-step explanation:

The y intercept is always the number on the out side next to the slope which is 2.391

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Find the perimeter of the figure below. Notice that one side length is not given.
sasho [114]

Answer:

58cm

Step-by-step explanation:

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Find the next term in the sequence 15 , 34 , 55 , 78 , 103
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The next term in the sequence will be increased by 27. The difference between 15 and 34 is 19 The difference between 34 and 55 is 21 The difference between 55 and 78 is 23 The difference between 78 and 103 is 25 Following this pattern, the next number will be 130

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Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

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Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

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Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

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3 years ago
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-by-step explanation:

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