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statuscvo [17]
2 years ago
15

How many solutions does each system of equations have?

Mathematics
1 answer:
melamori03 [73]2 years ago
6 0

Answers: y= 5x-4

Step-by-step explanation:

Steps:

[y=5x-4

12=15x-3y]

Substitute y=5x-4

[ 12=15x-3(5x-4) ]

Simplify

The solution is

y= 5x-4

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Answer:

mean: 26

minimum: 0

first q (lower): 5

median: 27

third q (upper): 44

max: 45

(all your answers for Aaron are correct as well:)

hope this helps:)

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2 years ago
Which expression is equal to 2X^2+7<br> (Simplify)
almond37 [142]

This expression cannot be simplified any further.

5 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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3 years ago
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QveST [7]

Answer:

Step-by-step explanation:

101/12

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3 years ago
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