4. Calcula la rapidez promedio de un perro que

A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in

777dan777 [17]

Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

Verify each statement

A) Each pack of folders has a volume of 60 cubic inches.

The statement is True

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

B) The box has a volume of about 720 cubic inches

The statement is True

Because

The volume of the box is equal to the volume of one pack of folders multiplied by 12

so

$V=(12)60=720\ in^{3}$

C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches

The statement is False

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}$

$900\ in^{3}\neq 1,200\ in^{3}$

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

The statement is True

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}$

$1,200\ in^{3}= 1,200\ in^{3}$

E) Each pack of folders has a volume of 24 cubic inches.

The statement is False

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

7 0

3 years ago

PLZ HELP!!!!!!! Evaluate. 43−4÷2⋅5 20 40 54 150

vitfil [10]

Isnt it 33 ////??? thats what i got.

6 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!!!!!!!

SVETLANKA909090 [29]

Data:

15 16 14 15 19 17

n=6 points

sum is 96

mean is 96/6 = 16

Now we look at the absolute deviations, each of which is the absolute value of a score minus the mean, basically the distance of the score to the mean .

Scores 15 16 14 15 19 17

AbsDev 1 0 2 1 3 1

The sum of the absolute deviations is 8 and there are six of them so the

Mean Absolute Deviation = 8/6 = 4/3

Answer: 2. 8/6

7 0

3 years ago

If w is a string of english letters a–z (all uppercase for the purposes of this problem), let wr denote the reverse of w; (train

Dennis_Churaev [7]

Answer:

$f(x)=\left \{\begin{array}{rl}26^{\frac{k}{2}}&\text{for k even}\\26^{\frac{k+1}{2}}&\text{for k odd}\end{array}\right.$

Step-by-step explanation:

Half the length of the palindrome can be any possible sequence of the 26 available letters. The other half is constrained to be the reverse of the same sequence. For odd length sequences, the middle letter can be any of the 26.

So, for k even, the number of palindromes is 26^(k/2). For k odd, the number is 26·26^((k-1)/2) = 26^)((k+1)/2).

5 0

3 years ago

Please help me with my homework.

Blababa [14]

Answer:

-3x + 6

Step-by-step explanation:

-3(x - 2) to find the equivalent of this expression, we need to multiply inside the parenthesis with -3 (with both x and -2)

-3(x - 2 = -3x + 6 (two negative expressions multiplied results in positive)

3 0

3 years ago