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Brums [2.3K]
3 years ago
12

I don’t know how to answer this question...

Mathematics
2 answers:
EleoNora [17]3 years ago
7 0

Answer:

the pic is nit clear but nice pfp tanjiro from demon slayer

also if u don't mind me asking have you watched the mugen train

blagie [28]3 years ago
4 0

Answer:

35

Step-by-step explanation:

5=25 and 5x5 would be the same thing

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There were n votes cast in an election. Ms. Gordy received 32% of the votes. Which expression represents the number of votes Ms.
Mamont248 [21]

Answer:

Step-by-step explanation:

4 0
2 years ago
Answer if you know
Arlecino [84]
I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set y=1.25 for this example.)

The length of each cross section (the side lying in the base) has length determined by the horizontal distance x between the y-axis x=0 and the curve y=\sqrt x. In terms of y, this distance is x=y^2. The height of each cross section is twice the value of y, so the area of each rectangular cross section should be 2y^3.

This means the volume would be given by the integral

\displaystyle\int_0^22y^3\,\mathrm dy
8 0
3 years ago
When two numbers are multiplied together, the result is 128.
fomenos

Answer:

32 and 4

Step-by-step explanation:

128=2^7

(8xa)xb=128

axb=2^4=16

(8x4)x4=128

3 0
2 years ago
If p(x)= 2x3+ a x2+ 3x–3 and f(x) = x3 + x2-4x+ aleave the same remainder when divided by x-2, find the value of a.
Luda [366]

Answer:

a = 3

Step-by-step explanation:

p(x) = 2x^{3} + ax^{2} +3x -3\\f(x) = x^{3} + x^{2} - 4x + a

To get the remainder when these polynomials are divided by x - 2, subsitute(x = 2) into both functions.

p(2) = 2(2^{3}) + a(2^{2}) +(3*2) -3\\p(2) = 19 - 4a\\f(2) = 2^{3} + 2^{2} - (4*2) + a\\f(2) = 4 + a

Since the remainders are the same, p(2) = f(2)

19 - 4a = 4 + a

19 - 4 = a + 4a

15 = 5a

a = 15/5

a = 3

6 0
3 years ago
Is this a function or no?
Andrei [34K]

Answer:

Nope

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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