All categories

3 years ago

Polly made a pinata for her sister's birthday party and wants to fill it with candy. If

Mathematics

1 answer:

devlian [24]3 years ago

5 0

Answer:

The volume of candy that is needed by Polly is 1,437.3 cubic inches

Step-by-step explanation:

What we have to do here is to find the volume of the sphere with a diameter of 14 inches

If the diameter is 14 inches, then the radius is 14/2 = 7 inches

This is because the radius is half the measure of the diameter

To find the volume of the sphere, we use the formula below;

Volume of sphere

= 4/3 * pi * r^3

pi = 22/7

r = 7 inches

Volume is;

4/3 * 22/7 * 7^3

= 4/3 * 22 * 7^2 = 1437.3 cubic inches

You might be interested in

Please help me need ASAPp

ipn [44]

It is the 4th option 0

7 0

3 years ago

-256÷457.6 a -16 b -1.6c 1.6 d 16

sp2606 [1]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Which of the following is the equation for the graph shown? PLS HELP... NEED ANSWER ASAP

lord [1]

Answer:

D the last one

Step-by-step explanation:

3 0

3 years ago

Tripp and Rico are two dogs. Tripp weighs exactly 35 pounds more than Rico. Together, they weigh exactly 49 pounds. How much doe

babymother [125]

Call the weights of the two dogs $t$ and $r$ .

We know that Tripp weights 35lbs more than Rico, or:
$t=r+35$

We also know that the total weight of both dogs is 49lbs.:
$t+r=49$

Now, by substitution:
$(r+35)+r=49$
$2r+35=49$
$2r+35-35=49-35$
$2r=14$
$r=\frac{14}{2}$
$r=7$
Rico weighs 7lbs.

Then:
$t=r+35$
$t=7+35$
$t=42$
Tripp weighs 42lbs.

To check our work:
$t+r=49$
$42+7=49$
$49=49$ CHECK!

5 0

3 years ago

The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin

quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

So, According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of The inscribed circle

So, the center of The inscribed circle is the point S

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

So, According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of The circumscribed circle

So, the center of The circumscribed circle is the point P

5 0

3 years ago