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Maru [420]
3 years ago
15

On a recent day,8euros were worth $11 and 32 euros were worth $44 .Enter an equation of the form Y = KX To show the relationship

between the number of euros and value in dollars.let y be the value in dollars and x be the numbers of euros. The equation is y=? NEED HELP!!!! Hey
Mathematics
2 answers:
kari74 [83]3 years ago
5 0
On a recent day, 8 euros were worth $11 and 40 euros were worth $55. Enter an equation of the form y = kx to show the relationship between the number of euros and the value in dollars. First solve k which is the slope so k = ( 55- 11) / ( 40 -8) = 1.375
Y= 1.375x
Lemur [1.5K]3 years ago
5 0

Answer:

1.3

Step-by-step explanation:

Question: On a recent day,8 euros were worth $11 and 32 euros were worth $44 .Enter an equation of the form Y = KX To show the relationship between the number of euros and value in dollars.let y be the value in dollars and x be the numbers of euros.

Notes:

  • 8 euro= $11
  • 32 euro= $44

Need:  Enter an equation of the form Y = KX To show the relationship between the number of euros and value in dollars.let y be the value in dollars and x be the numbers of euros.

In Y = K X

    |         |

    |         numbers of euros.

    value in dollars

Our first number: 8 euro = $11

Y=11

X=8

Then Convert:

11=K8

11=K*8 ---> 8*K=11

8K=11

11/8= 1.3

K=1.3

From your not so smart brainly user

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torisob [31]
8 bc 2/3 x 18= 12 and 12-4 = 8 :) sorry if im wrong tho
6 0
2 years ago
Find the absolute value
Ganezh [65]

Answer:

11

Step-by-step explanation:

|11| is a module, the numbers inside a module are equal to positive ones so
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5 0
2 years ago
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In 2010, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephon
Zepler [3.9K]

<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

Step-by-step explanation:

As per given , we have

H_0: \mu=9.4\\\\H_a:\mu\neq9.4, since H_0 is two-tailed so , the test is a two tail test.

Since population standard deviation is unknown, so we use t-test.

Critical value (two-tailed) for significance level of 0.01= t_{n-1,\alpha/2}=t_{49, 0.005}\pm2.609228

For n =50 , \overline{x}=8.6 and s= 4.8

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

t=\dfrac{8.6-9.4}{\dfrac{4.8}{\sqrt{50}}}\approx-1.18

Since test statistic value (-1.18) lies in critical interval (-2.609228, 2.609228), it means the null hypothesis is failed to reject.

We do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

4 0
3 years ago
Please help me asap!!!
Westkost [7]

Answer: immma guess that its c

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Step-by-step explanation:

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