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3 years ago

Why do silent mutations not affect the protein that the gene encodes?

1 answer:

4 0

Answer: Silent mutations occur when the change of a single DNA nucleotide within a protein-coding portion of a gene does not affect the sequence of amino acids that make up the gene's protein. ... And when the amino acids of a protein stay the same, researchers believed, so do its structure and function.

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What cell helps break down food to release energy

ANTONII [103]

Answer:

Its D mitochondria

Explanation:

lol i learned about cells for a longggg time so i know this

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3 years ago

when an infection occurs, the number of a. red blood cells increase b. red blood cells decrease c. white blood cells increase d.

Naddika [18.5K]

White blood cells increase as they are the cells that destroy pathogens

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3 years ago

Read 2 more answers

Polysaccharide digestion and glycogen breakdown involve sequential cleavage from ________ ends of glucose polymers.

Alex787 [66]

Sequential cleavage from the non-reducing terminals of glucose molecules is required for both glycogen degradation and polysaccharides hydrolysis.

Why non-reducing end is selected for digestion?

A polysaccharide's non-reducing end is the one where an anomeric carbon participates in the glycosidic connection. The elimination of carbohydrate remnants one at a time out from the non-reducing terminal occurs during glycogenolysis and polysaccharides hydrolysis.

For example, several enzymes are involved in glycogenolysis in the liver and muscle.

An example of such an enzyme is glycogen phosphorylase, which catalyzes the successive dissociation of the alpha 1->4 glycosidic bond that connects two glucose molecules at a non-reducing terminal of glycogen. The last glucose residue is eliminated as alpha-D-glucose 1-phosphate.

That is why non-reducing end of glucose is chosen for digestion or breakdown of the carbohydrate polymer.

Learn more about non-reducing here:

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1 year ago

A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by

bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that the probability that, given enough time, all tigers in the population will have horizontal stripes is 30% = 0.3.

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Available data:

Population size, N = 100 tigers
Number of Tigers with horizontal stripes = 30
Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

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You can learn more about Hardy-Weinberg equilibrium at

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6 0

3 years ago

Think about a bush in your back yard. Is it alive according to the characteristics of life? Why or why not?

ExtremeBDS [4]

Yes, plants are absolutely alive. They may not be conscious, sentiment beings, but they still perform cellular respiration, make waste products, and generate biomass (get bigger).

Hope this helps.

7 0

3 years ago