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siniylev [52]
3 years ago
5

What is the common point between: plants, fungi, bacteria, animals, zooplankton?

Biology
2 answers:
juin [17]3 years ago
8 0

Answer:

they all have cellwalls and yes they are also living creatures

Kruka [31]3 years ago
6 0

Answer:

They are all living creatures.... thats the only answer i think

Explanation:

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Compounds formed from attraction of oppositely charged ions are called
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<span>compounds formed from attraction of oppositely charged ions are called</span> ionic bond

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Select the best description of collagen from the lis:__________. 1. a protein that connects the extra cellular matrix to the cyt
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Answer:

Option-3

Explanation:

Collagen is one of the most abundant proteins of the animal kingdom as it is present in the connective tissue.

The collagen protein undergoes glycosylation that is carbohydrate molecules are attached to the protein.

The collagen fiber is produced by the chondroblasts which are suspended in the extracellular matrix of the cell. These fibers provide strength and flexibility to connective tissue.

Thus, Option-3 is the correct answer.Answer:

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4 years ago
In a crime scene, what would you place charcoal in found as evidence? And why?
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A plastic bag so that it can be cleanly put in
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3 years ago
Which reason is the best for choosing the ruler to
Murljashka [212]

Answer:

A meter stick is only marked in customary

units and is therefore inappropriate.

A tape measure is simply not accurate.

A ruler is a good length for meauring the

length of fairly small objects.

Only rulers are marked in centimeters, so no

other tool will work.

Explanation:

ummm..You Already Gave The Answer So .... Hope It Helps?!

8 0
3 years ago
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In a population of 150 toads, poisonous (P) is dominant over non-poisonous (p). According to the Hardy-Weinberg equation, the ex
aalyn [17]

Answer: Χ²=8.18

Explanation: In this population, the frequency of homozygote poisonous toads is:

p^{2} =\frac{100}{150}

p^{2} = 0.667

p = \sqrt{0.667}

p=0.82

For the homozygote non-poisonous toads:

q^{2} = \frac{5}{150}

q^{2} =0.034

q = \sqrt{0.034}

q = 0.18

The frequency for heterozygote poisonous toad, we can use the Hardy-Weinberg equation: p^{2} + 2pq + q^{2} = 1, in which, heterozygote frequency is given by 2pq

2pq = 2*0.82*0.18 = 0.3

Now, to compute the chi-square test, follow the instructions:

1) Find the observed values: in this case, they are the found frequency:

0.82       0.3         0.18

2) Find the expected values: As the question mentioned, the expected proportion is:

16            8             1

3) Subtract the observed value from the expected value:

0.82 - 16 = - 0.184          0.3 - 8 = -7.7             0.18 - 1 = - 0.818

4) Square each value from above:

(-0.184)² = 0.034            (-7.7)² = 59.3                 (-0.818)² = 0.77

5) Divide each value by expected value:

\frac{0.034}{16} = 0.0021                   \frac{59.3}{8} = 7.41                      \frac{0.77}{1} = 0.77

6) Add all the values and we will have the chi-square test:

Χ² = 0.0021 + 7.41 + 0.77 = 8.18

The chi-square test is Χ² = 8.18

8 0
3 years ago
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