Find the valid value(s) for x:
x2 +5x+6
= 1
x+3
1 answer:
Answer:
x=-1
Step-by-step explanation:
x+3≠0
x≠-3
x²+5x+6=x+3
x²+5x+6-x-3=0
x²+4x+3=0
x²+x+3x+3=0
x(x+1)+3(x+1)=0
(x+1)(x+3)=0
x+3≠ 0
so x+1=0
x=-1
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Answer:
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Step-by-step explanation:
Step-by-step explanation:
the first question
x²+x+5
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hope this was helpful
Answer:
Third option
Step-by-step explanation:
Because it has to be JKL or LKJ, (see how the K stays in the middle)
C = 2 x pi x r
C = 2 x pi x 15 = 30 π