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ra1l [238]
3 years ago
12

What is the distance

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

31 units

Step-by-step explanation:

Wrt distance formula

√(20-(-11))^2 +(-17-(-17))^2

=√(31)^2+(0)2

=√961+0

=√961

=31

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please help me on this I'm struggling on this thanks for your helping of you answer.please show your work:-)
PilotLPTM [1.2K]
A. is 1/4 so that would be 25%
sorry thats all i know
6 0
3 years ago
Read 2 more answers
Plz answer number 9 that’s all
Ray Of Light [21]
20/25
=4/5...........
4 0
3 years ago
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I need help solving systems of linear equations by substitution. <br> {4x+3y=14<br> 3x-2y=2
Sauron [17]

Answer:

A) 4x+3y=14

B) 3x-2y=2

We multiply equation A) by (2/3)

A) (8/3) x +2y = 28/3 then we add this to equation B)

B) 3x-2y=2

5 (2/3) x = 11 (1/3)

x = 2

A) 4 * 2 + 3 y = 14

A) 3y = 6

y = 2

Step-by-step explanation:

4 0
3 years ago
Write the sentence as an​ equation, using x as the variable. Then find the solution of the equation from the set of integers bet
Inessa05 [86]

Answer:

The solution of given equation is x = -4

Step-by-step explanation:

We are given the following in the question:

Let x be the variable such that

x \in (-12,12)

Relation:

The quotient of a number and 4 is negative 1

We can write the equation as:

\dfrac{x}{4} = -1

Solution:

\dfrac{x}{4} = -1\\\\\Rightarrow x = 4\times -1\\\Rightarrow x = -4

Thus, the solution of given equation is x = -4

4 0
3 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

4 0
2 years ago
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