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3 years ago

Can anyone help with this math problem

Mathematics

2 answers:

Ahat [919]3 years ago

6 0

Answer:

3702

Step-by-step explanation:

Initial population = 4500
Yearly decrease = 3.2%

<u>Formula:</u>

P(t) = 4500*((100 - 3.2)/100)^t = 4500*(0.968)^t
P- population, t- time in years after 2009

In our case t = 2015 - 2009 = 6

<u>Find the value:</u>

P(6) = 4500*(0.968)^6 = 3702 (rounded)

Marysya12 [62]3 years ago

3 0

Answer:

The frog population would be 3636.

Step-by-step explanation:

3.2% times 6 is 19.2%. And 19.2% of 4500 is 864. Then you do 4500-864 which is 3636.

Pls mark brainliest.

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2 years ago

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Carrie and brent leave home at the same time. carrie drives due east at a rate of 30 mph, while brent drives due south at a rate

Helga [31]

<h3>They are 268 miles far apart after 4 hours</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<u>Given :</u>

v₁ = 30 mph due east

v₂ = 60 mph due south

t = 4 hours

<u>Unknown :</u>

displacement = d = ?

<u>Solution :</u>

$d_1 = v_1 \times t$

$d_1 = 30 ~ mph \times 4 ~ h$

$d_1 = \boxed {120 ~ miles}$

$d_2 = v_2 \times t$

$d_2 = 60 ~ mph \times 4 ~ h$

$d_2 = \boxed {240 ~ miles}$

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$d \approx \boxed {268 ~ miles}$

<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

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