Can anyone help with this math problem
2 answers:
Answer:
Step-by-step explanation:
- Initial population = 4500
- Yearly decrease = 3.2%
<u>Formula:</u>
- P(t) = 4500*((100 - 3.2)/100)^t = 4500*(0.968)^t
- P- population, t- time in years after 2009
In our case t = 2015 - 2009 = 6
<u>Find the value:</u>
- P(6) = 4500*(0.968)^6 = 3702 (rounded)
Answer:
The frog population would be 3636.
Step-by-step explanation:
3.2% times 6 is 19.2%. And 19.2% of 4500 is 864. Then you do 4500-864 which is 3636.
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<h2>ANSWER</h2>
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-<em>secret_angel</em>-
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