Yea, sure thing...
So like, in a quadrilateral the sum of its angles will form 360°.
So,
(2x - 16)° + 2x° + x° + (x + 10)° = 360°
2x - 16 + 2x + x + x + 10 = 360
2x + 2x + x + x - 16 + 10 = 360
6x - 6 = 360
6x = 360 + 6
6x = 366
x = 366 ÷ 6
x = <u>6</u><u>1</u><u>.</u>
m<R = 2x° = 2 × 61 = <em><u>1</u></em><em><u>2</u></em><em><u>2</u></em><em><u>°</u></em><em><u>.</u></em>
Hope it helps ya mate :))
It’s a right angle triangle so u have it use Pythagorean theorem.
c^2 = a^2 + b^2
25^2 = 20^ 2 + b^2
625 = 400 + b^2
b^2 = 225
b = 15
X = 15
OK, wonderful. It should be very comfortable in there, since it's so small and fits so easily.
The circle can be placed completely inside the rectangle, in positions where it touches one side, two sides, or no sides. It's too small to touch thee sides or four sides all at the same time.
Do you have some kind of question to ask regarding the situation ?
Answer:
The horsepower of the carriage is 50
Step-by-step explanation:
Let the horsepower of the carriage=x
ATQ, 195+5=4x, x=50.