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Oksana_A [137]
3 years ago
7

Jack wanted to measure the perimeter of the triangular sandbox. One side was 4.5 feet. The second side was 6.4 feet. The third s

ide was 4.6 feet. What was the perimeter of the sandbox?
Group of answer choices
Mathematics
2 answers:
Natalka [10]3 years ago
7 0

Answer:

15.5 feet

Step-by-step explanation:

To work out the perimeter of any shape, you need to add the lengths of all the sides together for the total perimeter.

4.5 + 6.4 + 4.6 = 15.5 ft

rusak2 [61]3 years ago
3 0

Answer:15.5

Step-by-step explanation:

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Captain buys a 100g bar of chocolate. He eats 3/5 of his bar. How many grams of chocolate are left?
Andrews [41]

Answer:

40g of chocolate are left.

Step-by-step explanation:

3/5*100=300/5=60

100-60=40

5 0
3 years ago
What is the answer to log↓2(x)-3=1
sveticcg [70]
If u are trying to solve for x is that x=2
7 0
3 years ago
Is y varies directly as x, and y is 18 when x is 5 witch expression can be used to find the value of y when x is 11?
Svet_ta [14]
As the variation is direct we have:
 y = k * x

 Where,
 k: proportionality constant
 We must find the value of k.
 For this we use the following data:
 y is 18 when x is 5.
 Substituting values we have:
 18 = k * 5

 From here, let's clear k:
 k = 18/5

k = 3.6

 Then, replacing values we have:
 y = 3.6 * x

 For x = 11 we have:
 y = 3.6 * 11

y = 39.6
 Answer:
 
An expression that can be used to find the value of y when x is 11 is:
 
y = 3.6 * x

 When x = 11 we have:
 
y = 39.6
3 0
3 years ago
Solve the equation.<br><br> 23=z15
sladkih [1.3K]

Answer:

23 = z \times 15

Divide boty sides by 15

z =  \frac{23}{15}  = 1.53

The value of z is 23/15

4 0
3 years ago
Find a cubic polynomial that goes through points (4, – 22) and (3, - 26) and has tangents with slopes
Salsk061 [2.6K]

Let <em>f(x)</em> = <em>ax</em> ³ + <em>bx</em> ² + <em>cx</em> + <em>d</em>.

The graph of <em>f(x)</em> passes through (4, -22) and (3, -26), which means <em>f</em> (4) = -22 and <em>f</em> (3) = -26, so that

64<em>a</em> + 16<em>b</em> + 4<em>c</em> + <em>d</em> = -22

27<em>a</em> + 9<em>b</em> + 3<em>c</em> + <em>d</em> = -26

When the question says it has tangents at some point, I take that to mean the slope of the tangent line at that point is the given number. So <em>f '</em> (4) = 11 and <em>f '</em> (3) = -2. We have

<em>f '(x)</em> = 3<em>ax</em> ²+ 2<em>bx</em> + <em>c</em>

so that

48<em>a </em>+ 8<em>b </em>+ <em>c</em> = 11

27<em>a </em>+ 6<em>b</em> + <em>c</em> = -2

Solve the system:

• Eliminate <em>d</em> :

(64<em>a</em> + 16<em>b</em> + 4<em>c</em> + <em>d</em>) - (27<em>a</em> + 9<em>b</em> + 3<em>c</em> + <em>d</em>) = -22 - (-26)

→   37<em>a</em> + 7<em>b</em> + <em>c</em> = 4

• Eliminate <em>c</em> :

(48<em>a </em>+ 8<em>b </em>+ <em>c</em>) - (27<em>a </em>+ 6<em>b</em> + <em>c</em>) = 11 - (-2)

→   21<em>a</em> + 2<em>b</em> = 13

(48<em>a </em>+ 8<em>b </em>+ <em>c</em>) - (37<em>a</em> + 7<em>b</em> + <em>c</em>) = 11 - 4

→   11<em>a</em> + <em>b</em> = 7

• Eliminate <em>b</em>, then solve for <em>a</em> and the other variables:

(21<em>a</em> + 2<em>b</em>) - 2 (11<em>a</em> + <em>b</em>) = 13 - 2 (7)

-<em>a</em> = -1

<em>a</em> = 1   →   <em>b</em> = -4   →   <em>c</em> = -5   →   <em>d</em> = -2

Then

<em>f(x)</em> = <em>x</em> ³ - 4<em>x</em> ² - 5<em>x</em> - 2

7 0
4 years ago
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