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alex41 [277]
3 years ago
7

clark plans to fertilize his yard this summer. His yard is 40 feet wide a 60 feet long. thus included a 4 foot wide and 20 foot

long flower bed, which he will not fertilize. A bag of fertilizer costs $8.25 and covers 1,000 square feet. He also hopes to fertilize his neighbors yard the neighbors yard is 50 feet wide and proportional to clarks yard including a 5 foot wide and 30 foot long flower bed that will not be fertilized how long is the neighbors yard? set up a proportion

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0

I hope this explains it. Let me know if you have any other questions!

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Make p the subject of the formula 2(q+p) = 1+5q
NemiM [27]
2(q+p)=1+5q
2q+2p=1+5q
2p=1+(5q-2q)
2p=1+3q
p=(1+3q)/2
or p=1/2+3/2q
5 0
4 years ago
Solve the following riddle:
marusya05 [52]

403090

haven't done number riddles in a while, sorry if my answer is incorrect.

8 0
3 years ago
Read 2 more answers
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
4 years ago
The rectangular sandbox at the local community park has a width of 24.5 meters and its length is 31.7 meters. What is the perime
eduard
The answer is 112.4 because 24.5+24.5+31.7+31.7=112.4.
5 0
3 years ago
May someone help me with #2?
andrezito [222]

Answer:

number 2? ok it's 43

Step-by-step explanation:

hope this is helpful! have an amazing day :) God Bless you

6 0
3 years ago
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