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garri49 [273]
2 years ago
13

Find the slope of (-8.-4) and (-4,-9

Mathematics
2 answers:
mel-nik [20]2 years ago
8 0

Answer: -5/4

Step-by-step explanation:

Alexandra [31]2 years ago
4 0

Answer:

= -5/4

Step-by-step explanation:

To find the slope, we can use the slope formula

m = ( y2-y1)/(x2-x1)

   = ( -9 - -4)/( -4 - -8)

   = ( -9 +4)/( -4 +8)

    = -5/4

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A golf tournament has five rounds. The players are given scores for each round based on how many strokes they are above or below
Sedaia [141]

Answer:

(A) ∫₁⁵[Xₙ + k] where n ranges from 1 to 5

(B) 73.6

Step-by-step explanation:

The question is clear enough. Kudos!

So there are many players but we're focusing on Ricky.

Ricky has already recorded his score for each of the 5 rounds in the tournament.

The number of strokes in Ricky's record are to be added to or subtracted from a given number 72

ROUND 1:    [72 - 5] strokes = 67

ROUND 2:   [72 + 6] strokes = 78

ROUND 3:   [72 - 2] strokes = 70

ROUND 4:   [72 + 4] strokes = 76

ROUND 5:   [72 + 5] strokes = 77

(A) Write an expression to represent Ricky's total number of strokes for the five rounds.

Do not panic at this first exercise. You are to write an expression which when evaluated, will give the total number of strokes for all five rounds!

You are already given an abstract number '72' to work with in this question.

It is a fixed quantity which influences the value of strokes for each round.

We will represent this by an algebra, if we have to create the above required expression.

The expression will then be:

∫₁⁵[Xₙ + k] where n ranges from 1 to 5

You already know that the sigma sign '∫' represents summation and that's summation from the subscript '1' to the superscript '5'.

X₁ would be -5,   X₂ would be +6,   X₃ would be -2,   X₄ would be +4,   X₅ would be +5

K is the constant 72

(B) What was Ricky's average number of strokes per round?

Out of the 5 rounds, the average number of strokes per round would be

[67 + 78 + 70 + 76 +77] ÷ 5

= 368/5  = 73.6

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2 years ago
Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

Collect Like Terms

3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

-14 = k - 12a

k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

1 = 3a + 12a - 14

1 = 15a - 14

Collect Like Terms

15a = 1 + 14

15a = 15

Solve for a

a = \frac{15}{15}

a=1

Substitute 1 for a in k = 12a - 14

k = 12 * 1 - 14

k = 12 - 14

k = -2

3 0
2 years ago
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