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4 years ago

Can someone please tell me what x is?

Mathematics

2 answers:

jok3333 [9.3K]4 years ago

8 0

$Answer: \\ x \: will \: be \: 20^{\circ}$

yaroslaw [1]4 years ago

6 0

Answer:

Step-by-step explanation:

Hope this help :)

You might be interested in

At a school, 1 out of every 3 girls who tried out for basketball made the

nikdorinn [45]

Answer:

1:2

Step-by-step explanation:

because only one gets into the team

and the remaining two don't make the team

8 0

3 years ago

Susan, Deon, and Felipe sent a total of 160 text messages during the weekend. Felipe sent 4 times as many messages as Susan. Deo

Romashka [77]

Answer:

Susan sent 25 messages

Felipe sent 100 messages

Deon sent 35 messages

Step-by-step explanation:

160 = x + 4x + x + 10

160 = 6x + 10

6x = 150

x = 25

7 0

3 years ago

Please help me on this question, I was struggling with it for an hour from now.

krek1111 [17]

Answer:

Step-by-step explanation:

P(3) = ⅙

P(5) = ⅙

Trials are independent so,

P(3 then 5) = 1/6 × 1/6 = 1/36

4 0

3 years ago

Find the measure of the indicated angle. Please can you help? I need to show work.

777dan777 [17]

Answer:

64°

Step-by-step explanation:

∠RQP = 46°

∠PRQ = 180° - 110° = 70°

∠PRQ + ∠RQP + ∠RPQ = 180°

70° + 46 + ∠RPQ = 180°

116° + ∠RPQ = 180°

Find ∠RPQ

∠RPQ = 180° - 116° = 64°

4 0

3 years ago

For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: $z=\frac{x-\mu}{\sigma}$

Here z is 2.42 and μ is 790, substitute the respective values as shown.

$2.42=\frac{1637-790}{\sigma}$

$\sigma=\frac{847}{2.42}$

$\sigma=350$

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0

4 years ago