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jonny [76]
2 years ago
5

If ∧ ASC ≅ ∧ KSC then ∠8 is congruent to which angle?

Mathematics
1 answer:
zalisa [80]2 years ago
7 0

Answer:

B. angle 5

Step-by-step explanation:

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Find x <br> 3x+1=2x-2<br> show all work pls
spayn [35]
See attached photo:

8 0
3 years ago
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Thea scored an average of 13 points per game in her first 5 basketball games. In her 6th game, the average changed to 17 points
sammy [17]
Average of 5 games = 13
Total of 5 games = 13 x 5 = 65

Average of 6 games = 17
Total of 6 games = 102

6th game = 102 - 65 = 37

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Answer: Her score for the 6th game as 37.
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6 0
2 years ago
Line segment BC will be reflected over line m to form line segment BC. Which of the following statements must be true?
Len [333]

Answer:

<u>Option A</u>

Step-by-step explanation:

To reflect line segment BC over line m, BB' will be perpendicular to the line m

and line m bisector of BB'.

<u>So, the correct answer is option A</u>

A) Line m is the perpendicular bisector of line segment BB' and the line segment CC'

<u>Option b is wrong</u> , it is impossible for the line B'C' to be perpendicular to line BC. B'C' is the image of BC.

<u>Both option c and d is wrong</u> because the perpendicular distance from b to the line m not equal to the perpendicular distance from c to the line m.

7 0
3 years ago
How do you write “twice a number less than 3 is 17” as an equation?
ki77a [65]

Answer:

2 x 3 < 17

Step-by-step explanation:

Greater than and/or less than step by step equasion.

4 0
3 years ago
The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
     i) bisect the angles so m(ODC)=60°/2=30°

     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

6 0
3 years ago
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