Find the zero of the function:<br> y= 11x^2+25x-24

over 6 days, Dan jogged 7.5 miles, 6 miles, 3 miles, 3 miles, 5.5 miles and 5 miles what is the mean distance that Dan jogged ea

Inga [223]

To start add together all of the miles over 6 days. Added together it equals 30 miles.

Then take 30 miles divided by how many days.
30 divided by 6.
30 divided by 6=5
5 miles is the mean distance.

7 0

3 years ago

Melissa has 14 reports to file. If each report takes an average of 1 hour and 15 minutes to file, how long will it take her to f

ivolga24 [154]

0.7 * 14 = 9.8
60 + 15 = 75 minutes
9.8 * 75 = 735 minutes
735 ÷ 60 =
12 hours and 15 minutes

8 0

3 years ago

Tickets for a drumline competition cost $5 at the gate and $3 in advance. One hundred more tickets were sold in advance than at

irina [24]

Answer:

The number of tickets sold at the gate is $G = 211.25$

The number of tickets sold in advance is $A = 311.25$

Step-by-step explanation:

From the question we are told that

The cost of a tickets at the gate is $a = \$ 5$

The cost of a ticket in advance is $b = \$ 3$

Let the number of ticket sold in the gate be G

Let the number of ticket sold in advance be A

From the question we are told that

One hundred more tickets were sold in advance than at the gate and this can be mathematically represented as

$G + 100 = A$

From the question we are told that

The total revenue from ticket sales was $1990 and this can be mathematically represented as

$5 G + 3A = 1990$

substituting for A in the equation above

$5 G + 3[G + 100]= 1990$

$5 G + 3G + 300= 1990$

$8G + 300= 1990$

$8G = 1690$

=> $G = 211.25$

Substituting this for G in the above equation

$5 [211.25] + 3A = 1990$

=> $3A = 1990 - 1056.25$

=> $A = 311.25$

3 0

3 years ago

Helpp!!<br> Simplify : [( 4 1/6 + 2 1/3 ) ÷ 4 1/3 ] - 1 1/2

Nadusha1986 [10]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{0}}}}}$

Step-by-step explanation:

$\sf{ [ (4 \frac{1}{6} + 2 \frac{1}{3} ) \div 4 \frac{1}{3}] - 1\frac{1}{2} }$

Convert the mixed numbers into improper fraction

$\longrightarrow{ \sf{ [ ( \frac{25}{6} + \frac{7}{3} ) \div \frac{13}{3}] - \frac{3}{2}}}$

Add the fractions : 25 / 6 and 7 / 3

While performing addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fraction.

To do so, first take the L.C.M of 6 and 3 which results to 6

$\longrightarrow\sf{ [( \frac{25 + 7 \times 2}{6} ) \div \frac{13}{3} ] - \frac{3}{2}}$

$\longrightarrow{ \sf{ [( \frac{25 + 14}{6} ) \div \frac{13}{3} ] - \frac{3}{2} }}$

$\longrightarrow{ \sf{ [ \frac{39}{6} \div \frac{13}{3}] - \frac{3}{2} }}$

Multiply the dividend by the reciprocal of the divisor.

Reciprocal of any number or fraction can be obtained by interchanging the position of numerator and denominator

$\longrightarrow{ \sf{ [ \frac{39}{6} \times \frac{3}{13} ] - \frac{3}{2}}}$

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term

$\longrightarrow{ \sf{ [ \frac{39 \times 3}{6 \times 13} ] - \frac{3}{2}}}$

$\longrightarrow{ \sf{ [ \frac{117}{78} ] - \frac{3}{2} }}$

$\longrightarrow{ \sf{ \frac{3}{2} - \frac{3}{2} }}$

While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same

$\longrightarrow{ \sf{ \frac{3 - 3}{2} }}$