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fenix001 [56]
3 years ago
14

Help me I'm struck it to hard I dont get it ​

Mathematics
1 answer:
lbvjy [14]3 years ago
5 0
You add four four times !
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How would you determine the axis of symmetry in order to graph x^2 = 8y^2.
Tanya [424]
The picture illustrates the definition. The point P is a typical point on the parabola so that its distance from the directrix, PQ, is equal to its distance from F, PF. The point marked V is special. It is on the perpendicular line from F to the directix. This line is called the axis of symmetry of the parabola or simply the axis of the parabola and the point V is called the vertex of the parabola. The vertex is the point on the parabola closest to the directrix.

Finding the equation of a parabola is quite difficult but under certain cicumstances we may easily find an equation. Let's place the focus and vertex along the y axis with the vertex at the origin. Suppose the focus is at (0,p). Then the directrix, being perpendicular to the axis, is a horizontal line and it must be p units away from V. The directrix then is the line y=-p. Consider a point P with coordinates (x,y) on the parabola and let Q be the point on the directrix such that the line through PQ is perpendicular to the directrix. The distance PF is equal to the distance PQ. Rather than use the distance formula (which involves square roots) we use the square of the distance formula since it is also true that PF2 = PQ2. We get

<span>(x-0)2+(y-p)2 = (y+p)2+(x-x)2. 
x2+(y-p)2 = (y+p)2.</span>If we expand all the terms and simplify, we obtain<span>x2 = 4py.</span>

Although we implied that p was positive in deriving the formula, things work exactly the same if p were negative. That is if the focus lies on the negative y axis and the directrix lies above the x axis the equation of the parabola is

<span>x2 = 4py.</span><span>The graph of the parabola would be the reflection, across the </span>x<span> axis of the parabola in the picture above. A way to describe this is if p > 0, the parabola "opens up" and if p < 0 the parabola "opens down".</span>

Another situation in which it is easy to find the equation of a parabola is when we place the focus on the x axis, the vertex at the origin and the directrix a vertical line parallel to the y axis. In this case, the equation of the parabola comes out to be

<span>y2 = 4px</span><span>where the directrix is the verical line </span>x=-p and the focus is at (p,0). If p > 0, the parabola "opens to the right" and if p < 0 the parabola "opens to the left". The equations we have just established are known as the standard equations of a parabola. A standard equation always implies the vertex is at the origin and the focus is on one of the axes. We refer to such a parabola as a parabola in standard position.

Parabolas in standard positionIn this demonstration we show how changing the value of p changes the shape of the parabola. We also show the focus and the directrix. Initially, we have put the focus on the y axis. You can select on which axis the focus should lie. Also you may select positive or negative values of p. Initially, the values of p are positive. 

5 0
4 years ago
Whats the GCF of 49 and 4
Irina18 [472]
The greatest common factor is 1 because there is not a number that goes into or will multiply and get 49 and 4. 49 is an odd number and 4 is an even number so the GCF is 1.
5 0
3 years ago
are the graphs of the lines in the pair parallel? explain. y equals two thirds x minus 17. 4 x minus 6 y equals negative 6. a. n
nasty-shy [4]
The slope of the line is the quotient when the negative of the numerical coefficient of x is divided by the numerical coefficient of y. The slope of the first line is 2/3 and that of the second line is -4/-6 or 2/3. Thus, the answer is letter C. 
6 0
3 years ago
Find the midpoint of the segment between the points (8,-10) and (-10,-8)
Delvig [45]

Answer:

(-1, -9)

Step-by-step explanation:

Recall that for 2 points (x1, y1) and (x2,y2)

the midpoints are given by

x ordinate = \frac{x1+x2}{2}

y ordinate = \frac{y1+y2}{2}

In our case x1 = 8, y1 = -10, x2 = -10, y2=-8

x ordinate = \frac{x1+x2}{2}  = [8 + (-10) ] / 2 = -1

y ordinate = \frac{y1+y2}{2} = [-10 + (-8) ] / 2 = -9

hence midpoint is (-1, -9)

7 0
3 years ago
Read 2 more answers
The lines shown below are parallel.if the green line has a slope of -1,what is the slope of the red line?
vova2212 [387]

Answer:

-1

Step-by-step explanation:

If a line is parallel on a graph, then that means that they will descend/climb at the same rate. Therefore, the slope of this line is also -1.

Hope this helped!

4 0
3 years ago
Read 2 more answers
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