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adoni [48]
3 years ago
11

The side of a square is (4x-2y) what is the perimeter of the square

Mathematics
1 answer:
Sergio [31]3 years ago
5 0
Go to mathpa it's under algebra calculator very helpful
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satela [25.4K]

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2 years ago
One-eight of 32 students in the class went abroad for fall break. how many students went aboard
Anna35 [415]

Answer:4

Step-by-step explanation: 32\8 = 4

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1 year ago
*15 points please help easy question*
Igoryamba

Answer:

x = \sqrt{13}

Step-by-step explanation:

The segment from the vertex to the base is a perpendicular bisector.

Using Pythagoras' identity on the right triangle on the left.

x² = 2² + 3² = 4 + 9 = 13 ( take the square root of both sides )

x = \sqrt{13}

6 0
2 years ago
MATH QUESTION!! WILL MARK BRAINLIEST!! PAST DUE HELP ASAP!!!
monitta

Answer:

<em>Proof below</em>

Step-by-step explanation:

<u>Right Triangles</u>

In any right triangle, i.e., where one of its internal angles is 90°, some interesting relations stand. One of the most-used is Pythagora's Theorem.

In a right triangle with shorter sides a and b, and longest side c, called the hypotenuse, the following equation is satisfied:

c^2=a^2+b^2

The image provided in the question shows a line passing through points A(0,4) and B(3,0) that forms a right triangle with both axes.

The origin is marked as C(0,0) and the point M is the midpoint of the segment AB. We have to prove.

CM=\frac{1}{2}AB

First, find the coordinates of the midpoint M(xm,ym):

\displaystyle x_m=\frac{0+3}{2}=1.5

\displaystyle y_m=\frac{4+0}{2}=2

Thus, the midpoint is M( 1.5 , 2 )

Calculate the distance CM:

CM=\sqrt{(1.5-0)^2+(2-0)^2}

CM=\sqrt{2.25+4}=\sqrt{6.25}=2.5

CM=2.5

Now find the distance AB:

AB=\sqrt{(3-0)^2+(4-0)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}

AB=5

AB/2=2.5

It's proven CM is half of AB

3 0
3 years ago
Im bored put something funny as an answer and ill give brainliest
kvv77 [185]

Answer:

Q: How do you get a squirrel to like you? A: You act like a nut!

Step-by-step explanation:

8 0
3 years ago
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