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juin [17]
3 years ago
6

What is equivalent to 7 x 7 x 7 x 7 x7 x 7? 7 (5 as exponent), 7 (6 as exponent), 6 (7 as exponent), 7 (7 as exponent).

Mathematics
2 answers:
Ivan3 years ago
6 0

Answer:

7 (6 as exponent)

Step-by-step explanation:

Given the repeated product of a number to be expressed in exponential terms, we take the number as the base and the number of times it is multiplied as the exponent or power.

As such, given 7 x 7 x 7 x 7 x7 x 7

the base is 7 and since the number of 7s being multiplied is 6, the result is

7 exponent 6 which may be written as 7^6

Ymorist [56]3 years ago
4 0

Answer:

Step-by-step explanation:

7^6

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6 Which equation has a solution of s = 9.5 ? F -5s = -47.5 G -3 + s = 12.5 H --2s 19 J –1 + s = 10.5​
earnstyle [38]

Answer:

F. -5s = -47.5

Step-by-step explanation:

F. -5s = -47.5

s = -47.5 / -5

s =  9.5

This is the correct option

G. -3 + s = 12.5

s = 12.5 + 3

s = 15.5 (Incorrect option)

J. –1 + s = 10.5​

s = 10.5 + 1

s = 11.5 (Incorrect option)

5 0
3 years ago
15 - 9 + 2.65 + 1.35 + 2(1.74)
statuscvo [17]
15 - 9 + 2.65 + 1.35 + 3.48
6 + 2.65 + 1.35 + 3.48
8.65 + 1.35 + 3.48
10 + 3.48
13.48
3 0
3 years ago
!000000000 to the 5th power?
Elena L [17]

Answer:

i will just give you the answer <u><em>1e+45</em></u>

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\&#10;slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\&#10;-------------------------------\\\\

\bf \boxed{5i+12j}\implies &#10;\begin{array}{rllll}&#10;\ \textless \ 5&,&12\ \textgreater \ \\&#10;x&&y&#10;\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}&#10;\\\\\\&#10;slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}&#10;\\\\\\&#10;\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
4 years ago
What is the value of 7/9 x 2/3 ?
Elan Coil [88]

Answer:

42/81 or 0.5185185

Step-by-step explanation:

7/9 × 2/3

The hcf of 9 and 3 is 9

7/9 × 2/3

2/3 × 3= 6/9

7/9× 6/9 = 42/81 or 0.5185185

5 0
4 years ago
Read 2 more answers
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