To determine the center points and the radius of the circle, we can either graph the equation or write it in a form where the center and the radius can be easily be seen. For this, we use the second method. The form should be:
(x - h)^2 + (y-k)^2 = r^2
(h,k) represent the center and r the radius
We do as follows:
<span>x2 + y2 -6x + 10y + 25 = 0
</span>x2 -6x + y2<span> + 10y = - 25
x2 - 6x + 9 + </span> y2 + 10y + 25 = -25 + 9 + 25 = 9
(x - 3)^2 + (y + 5)^2 = 3^2
Therefore, the center is at ( 3,-5) and the radius is 3 units.
Your doing it just fine that's the correct way .
Take a quadratic equation in standard form:
If there exists a sum of two numbers that equal b, whose addends produce a product that equals c. You can rewrite the quadratic as a product of two binomials.
For example take
When thought through throughly, -5 had addends, -2 and -3 that produce 6 when multiplied
Thus, we can rewrite the quadratic as.
It would be y=4x-2 because:
8x-3y=6-4x
-8x -8x
-3y=6-12x
/-3 /-3 /-3
y=-2+4x
y=4x-2
