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sattari [20]
3 years ago
11

10 points eBookReferencesCheck my workCheck My Work button is now enabled1Item 9 Consider the following observations of a series

: Year 1 Year 2 Year 3 Year 4 100 120 160 170 a. Calculate the growth rates for Year 1–Year 2, Year 2–Year 3, and Year 3–Year 4. (Round your answers to 4 decimal places.) b. Calculate the average growth rate. (Enter your answer as a percentage, rounded to 2 decimal places, using intermediate calculations rounded to at least 4 decimal places.)
Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0

Answer:

Growth\ Rate = 0.2000 --- Year 1 to 2

Growth\ Rate = 0.3333 --- Year 2 to 3

Growth\ Rate = 0.0625 --- Year 3 to 4

Average\ Growth\ Rate = 19.86\%

Step-by-step explanation:

Given

\begin{array}{cc}{Year\ 1} & {100} & {Year\ 2} & {120} & {Year\ 3} & {160} & {Year\ 4} & {170} \ \end{array}

Solving (a): Growth Rates between each year

For Year 1 to 2.

Growth\ Rate = \frac{Year\ 2 - Year\ 1}{Year\ 1}

Growth\ Rate = \frac{120-100}{100}

Growth\ Rate = \frac{20}{100}

Growth\ Rate = 0.2000

For Year 2 to 3.

Growth\ Rate = \frac{Year\ 3 - Year\ 2}{Year\ 2}

Growth\ Rate = \frac{160-120}{120}

Growth\ Rate = \frac{40}{120}

Growth\ Rate = 0.3333

For Year 3 to 4.

Growth\ Rate = \frac{Year\ 4 - Year\ 3}{Year\ 3}

Growth\ Rate = \frac{170-160}{160}

Growth\ Rate = \frac{10}{160}

Growth\ Rate = 0.0625

Solving (b): The average growth rate

This is calculated as by calculating the mean value of the growth rates in (a)

Average\ Growth\ Rate = \frac{1}{3}(0.2000 + 0.3333 + 0.0625)

Average\ Growth\ Rate = \frac{1}{3}(0.5958)

Average\ Growth\ Rate = \frac{1}{3}*0.5958

Average\ Growth\ Rate = 0.1986

Convert to percentage

Average\ Growth\ Rate = 0.1986 * 100\%

Average\ Growth\ Rate = 19.86\%

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Answer: The required probability is 0.1328.

Step-by-step explanation:

Since we have given that

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Probability of success = p = defective rate = 3% = 0.03

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P(X=1)=^5C_1(0.03)^1(0.097)^4\\\\P(X=1)=0.1328

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The manufacturer of hardness testing equipment uses​ steel-ball indenters to penetrate metal that is being tested.​ However, the
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Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

\bar{x_1} = 1/9( 50+57+......+51+53)

=530/9

=58.89

\bar{x_2}= 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s=\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}

 = \sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}

= \sqrt{1007.76/16}

=7.93

sd = s*\sqrt{(1/n1)+(1/n2)}

=7.93*\sqrt{(1/9)+(1/9)}

=7.93* 0.47

=3.74

For 95% confidence level Z (\alpha /2) =1.96

confidence interval is

d\pm Z(\alpha /2)*s_d

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

3 0
3 years ago
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