The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

which would be

in sigma notation.
To do this, notice that the denominator in each term is a power of 2, starting with
and ending with
. So in sigma notation, this series is

<span>83.212121 or fraction form is </span>83 7/33<span> </span>
Answer:
Step-by-step explanation:
Answer:(A)= (-x^11)/(y^7)
(B)= (1/12xy^5)
Step-by-step explanation:
(A) (3x^3y^-2)(-2x^-3y^2)^-5/(6x^7y^-5)
[(3x^3y^-2)(-2x^15y^-10)]/(6x^7y^-5)
(6x^18y^5)/(-6x^7y^12)
(-6x^11)/(6y^7)
(-x^11)/(y^7)
(B) [(12x^-3y^5)/(x^-4)]^-1
(1/12xy^5)
Yes it is it would not be able to go any lower
good job :)
Answer:
25 square units
Step-by-step explanation:
square 1 = 100 units (perimeter)
therefore each side = 25 units
square 2 = 225 square units (area)
therefore each side = 15 units
The sequence gradually decreases by 10.
Therefore square 3 each side would be 5 units.
To find the Area = 5×5
= <u>25 square units.</u>