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TEA [102]
3 years ago
10

9х - 5 = 1/4(16х + 60) solve for xis the answer 20 or something else?​

Mathematics
1 answer:
Mice21 [21]3 years ago
3 0

Answer:

9x - 5 = 1/4(16x+60)

9x - 5 = 4x + 15

5x =20

x=4

Let me know if this helps!

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Suppose you work for a sporting goods company, and you want to order shipping boxes for bike helmets. Each helmet is already pac
madreJ [45]

Answer:  n^2+6n-135=0

Step-by-step explanation:

The length, width and height of the smaller box are n inches , n inches and 8 inches respectively,

And, According to the question,

The shipping boxes has 2 inches extra width than that of smaller box and 4 inches extra length than that of smaller box, Also, The height of the shipping box should be the same as the helmet box.

Thus, the Length of the shipping box = (n + 4) inches

Width = (n+2) inches and height = 8 inches

Thus, the volume of the shipping box,

V = (n+4)\times (n+2)\times 8=(n^2+6n+8)8=8n^2+48n+64

But, V = 1,144 cubic inches,

⇒ 8n^2+48n+64=1144

⇒ n^2+6n+8=143

⇒  n^2+6n-135=0

Which is the required equation that models the volume of the shipping box.

8 0
3 years ago
Find: (i) (-3/5) + (-2/7) (ii) (-2/7) -<br>(-3/14) (iii) (- 4/ 9) = (- 2/3)​
Sholpan [36]

Answer:

I. 1/5

II. -1/14

III. 2/9

Step-by-step explanation:

(i) (-3/5) + (-2/7)

Opening up the bracket;

3/5 - 2/5 =

Lowest common multiple (LCM) = 5

(3 - 2)/5

= 1/5

(ii) (-2/7) - (-3/14)

Opening up the bracket;

-2/7 + 3/14 =

Lowest common multiple (LCM) = 14

(-4 + 3)/14 = -1/14

(iii) (-4/ 9) = (- 2/3)

Rearranging the fraction, we have;

-4/9 + 2/3 =

Lowest common multiple (LCM) = 9

(-4 + 6)/9 = 2/9

5 0
3 years ago
Need help from 7-9 pls
expeople1 [14]

Answer:

b 5 a 6 b 7

Step-by-step explanation:

5 0
3 years ago
The mad scientist will need two fifth of the potions how many potion is that
gulaghasi [49]
40% if you are asking for percent that’s you answer
7 0
3 years ago
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Use the grouping method to factor x3 + x2 + 2x + 2.
chubhunter [2.5K]

x^3+x^2+2x+2

$x^2(x+1)+2(x+1)=(x^2+2)(x+1)$

4 0
3 years ago
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